Một cửa hàng trong 3 ngày bán được có 2 tấn đường. Ngày đầu bán được 800kg. Ngày thứ hai bán được số đường bằng 4/5 số đường bán được trong ngày đâu. Hỏi ngày thứ ba bán được bao nhiêu ki - lô - gam đường ?
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Đổi 2 tấn = 2000 kg
Ngày thứ hai bán được số kg đường là
\(800\cdot\frac{4}{5}=640\)( kg)
Ngày thứ 3 bán được số kg đường là
\(2000-800-640=560\)( kg)
2 tấn = 2000 kg
ngày thứ 2 bán được :
800 x 4/5 = 640 (kg)
ngày thứ 3 bán được :
2000 - 800 - 640 = 560 (kg)
1 tấn = 1000 kg
Ngày thứ hai bán được : 300 x 2 = 600 (kg)
Hai ngày đầu bán được : 300 + 600 = 900 (kg)
Ngày thứ ba bán được : 1000 - 900 = 100 (kg)
Đáp số: 100kg đường.
1 tấn = 1000 kg
Ngày thứ hai bán được : 300 x 2 = 600 (kg)
Hai ngày đầu bán được : 300 + 600 = 900 (kg)
Ngày thứ ba bán được : 1000 - 900 = 100 (kg)
Đáp số: 100kg đường.
Đổi 1,5 tấn = 1500kg
Ngày thứ 2 cửa hàng bán được: 350x2 = 700(kg)
Ngày thứ 3 cửa hàng bán được: 1500-700-350=450(kg)
đổi 2 tấn=2000kg
tự tóm tắt nhé:
ngày thứ hai bán đc số kg đường là:
800x4/5=...........(kg)
ngày thứ 3 bấn đc số kg đường là:
2000-800-.....=........
đ/s
xin lỗi vì mk ko tính ra cho bn nhé
Ta có :1 tấn=1000kg
Ngày thứ 2 bán đc số đường là :300x2=600(kg)
=>Ngày thứ 3 bán đc số đường là:1000-300-600=100(kg)
Đáp số:100kg đường.
1 tấn = 1000 kg đường
Ngày thứ 2 bán được: 300 x 2 = 600 ( kg )
Ngày thứ 3 bán được: 1000 - 600 - 300 =100 (kg)
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Bài giải
Ngày thứ hai cửa hàng bán được số kg đường là: 750 : 2 = 375 kg
Trung bình mỗi ngày cửa hàng đó bán được số ki-lô-gam đường là:
(750+375+630) : 3 = 585 kg
Đáp số: 585 kg
Giải:
2 tấn = 2000kg
Ngày thứ hai cửa hàng bán được số đường là :
400 x \(\frac{3}{5}\) = 240 (kg)
Cả hai ngày cửa hàng bán được số đường là :
400 + 240 = 640 (kg)
Cửa hàng còn lại số đường là :
2000 - 640 = 1360 (kg)
Đáp số: 1360 kg đường
Đổi 2 tấn = 2000 kg
Ngày thứ 2 bán được số kg đường là :
400 : 5 x 3 = 240 (kg đường)
Cửa hàng còn lại số kg đường là :
2000 - ( 400 + 240 ) = 1360 (kg đường)
Đáp số : 1360 kg đường
Đổi: 2 tấn = 2000 kg
Số kg đường ngày hai bán được:
\(800\times\dfrac{4}{5}=640\left(kg\right)\)
Số kg đường ngày 3 bán được:
\(2000-800-640=560\left(kg\right)\)
Ngày thứ ba bán được:
\(2000-800-800\cdot\dfrac{4}{5}=560\left(kg\right)\)