Question

[pham thi hoa]

bài 6; Tìm số tự nhiên x, biết;

a, \(^{x^2}\)= 4                      b, \(^{x^2}\)= 64             c, 6 \(x^3\)- 8 = 40

d, ( 2. x - 1 ) ^{2 _{- = 49          e, 2}x  _{: 16 = 2}5        _{f, 4}5 _{: 4}x = 16}

Answer 1

[💋Bevis💋]

\(a,x^2=4\Rightarrow x^2=2^2\Rightarrow x=2\)

\(b,x^2=64\Rightarrow x^2=8^2\Rightarrow x=8\)

\(c,6x^3-8=40\Rightarrow6x^3=48\Rightarrow x^3=8\Rightarrow x^3=2^3\Rightarrow x=2\)

\(d,\left(2x-1\right)^2=49\Rightarrow\left(2x-1\right)^2=7^2\Rightarrow2x-1=7\Rightarrow x=4\)

\(e,2^x:16=2^5\Rightarrow2^x:16=32\Rightarrow2^x=512\Rightarrow2^x=2^9\Rightarrow x=9\)

\(f,4^5:4^x=16\Rightarrow1024:4^x=16\Rightarrow4^x=64\Rightarrow4^x=4^3\Rightarrow x=3\)

Answer 2

[Jennie Kim]

a, x^2 = 4

=> x = 2 hoặc x = -2

b, x^2 = 64 

=> x = 8 hoặc x = -8

c, 6x^3 - 8 = 40

=> 6x^3 = 48

=> x^3 = 8

=> x = 2

d, (2x - 1)^2 = 49

=> 2x - 1 = 7 hoặc 2x - 1 = -7

=> 2x = 8 hoặc 2x = -6

=> x = 4 hoặc x = -3

e, 2^x : 16 = 2^5

=> 2^x : 2^4 = 2^5

=> 2^x = 2^9

=> x = 9 

f, 4^5 : 4^x = 16

=> 4^5 - x = 4^2

=> 5 - x = 2

=> x = 3