Phân tích thành nhân tử
a) 6x^2-11x+3
b)2x^2+3x-27
c)2x^2-5xy+3y^2
d)2x^2-5xy-3y^2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) 6x2 - 11x + 3
= 6x2 - 9x - 2x + 3
= 3x ( 2x - 3 ) - ( 2x - 3 )
= ( 2x - 3 ) ( 3x - 1 )
b ) 2x2 + 3x - 27
= 2x2 - 6x + 9x - 27
= 2x ( x - 3 ) + 9 ( x - 3 )
= ( x - 3 ) ( 2x + 9 )
c ) 2x2 - 5xy - 3y2
= 2x2 - 2xy - 3xy - 3y2
= 2x ( x - y ) - 3y ( x - y )
= ( x - y ) ( 2x - 3y )
Ta có:
a) 6x2 - 11x +3 = 2x(3x-1)-3(3x-1)=(2x-3)(3x-1)
b) 2x2 +3x - 27= x(2x+9)-3(2x+9)=(x-3)(2x+9)
c) 2x2 -5xy-3y2 = 2x(x-3y)+y(x-3y)=(2x+y)(x-3y)
a) 6x2 - 11x + 3 = 6x2 - 2x - 9x + 3 = 2x(3x - 1) - 3(3x - 1) = (3x - 1)(2x - 3)
b) 2x2 + 3x - 27 = 2x2 - 6x + 9x - 27 = 2x(x - 3) + 9(x - 3) = (x - 3)(2x + 9)
c) 2x2 - 5xy - 3y2 = 2x2 + xy - 6xy - 3y2 = x(2x + y) - 3y(2x + y) = (2x + y)(x - 3y)
6x2-11x+3
<=> 6x2 - 2x -9x +3
<=> 2x( 3x -1) - 3(3x-1)
<=> (3x-1)(2x-3)
d) \(2x^2-3x-27\)
\(=\left(2x^2+6x\right)-\left(9x+27\right)\)
\(=2x\left(x+3\right)-9\left(x+3\right)\)
\(=\left(2x-9\right)\left(x+3\right)\)
e) \(2x^2-5xy-3y^2\)
\(=\left(2x^2+xy\right)-\left(6xy+3y^2\right)\)
\(=2x\left(x+y\right)-3y\left(x+y\right)\)
\(=\left(2x-3y\right)\left(x+y\right)\)
a) \(6^2-11x+3\)
\(=6x^2-2x-9x+3\)
\(=\left(6x^2-2x\right)-\left(9x-3\right)\)
\(=2x\left(3x-1\right)-3\left(3x-1\right)\)
\(=\left(2x-3\right)\left(3x-1\right)\)
b)\(2x^2+3x-27\)
\(=2x^2-6x+9x-27\)
\(=\left(2x^2-6x\right)+\left(9x-27\right)\)
\(=2x\left(x-3\right)+9\left(x-3\right)\)
\(=\left(2x+9\right)\left(x-3\right)\)
c)\(2x^2-5xy+3y^2\)
\(=2x^2-2xy-3xy+3y^2\)
\(=\left(2x^2-2xy\right)-\left(3xy-3y^2\right)\)
\(=2x\left(x-y\right)-3y\left(x-y\right)\)
\(=\left(2x-3y\right)\left(x-y\right)\)
d)\(2x^2-5xy-3y^2\)
\(=2x^2+xy-6xy-3y^2\)
\(=\left(2x^2+xy\right)-\left(6xy+3y^2\right)\)
\(=x\left(2x+y\right)-3y\left(2x+y\right)\)
\(=\left(x-3y\right)\left(2x+y\right)\)