Tính nhanh:
a) A=131*(35-207)-35*31+131*207
b) B=2^15*7-2^16/5*2^15
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\(A=131\cdot\left(35-27\right)-35\cdot31+131\cdot207\\ A=131\cdot35+131\cdot27-35\cdot31+131\cdot207\\ A=35\cdot\left(131-31\right)+131\cdot\left(27+207\right)\\ A=35\cdot100+131\cdot234\\ A=3500+30654=34154\)
\(a,\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{13}{28}\\ b,\dfrac{3}{8}-\dfrac{5}{16}=\dfrac{1}{16}\\ c,\dfrac{7}{5}-\dfrac{2}{3}=\dfrac{11}{15}\\ d,\dfrac{31}{36}-\dfrac{5}{6}=\dfrac{1}{36}\)
\(a,\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{21}{28}-\dfrac{8}{28}=\dfrac{13}{28}\)
\(b,\dfrac{3}{8}-\dfrac{5}{16}=\dfrac{6}{16}-\dfrac{5}{16}=\dfrac{1}{16}\)
\(c,\dfrac{7}{5}-\dfrac{2}{3}=\dfrac{21}{15}-\dfrac{10}{15}=\dfrac{11}{15}\)
\(d,\dfrac{31}{36}-\dfrac{5}{6}=\dfrac{31}{36}-\dfrac{30}{36}=\dfrac{1}{36}\)
......................?
mik ko biết
mong bn thông cảm
nha ................
Bài 1:
\(=\dfrac{-1}{2}+\dfrac{3}{5}-\dfrac{1}{9}+\dfrac{1}{131}+\dfrac{2}{7}+\dfrac{4}{35}-\dfrac{7}{18}\)
\(=\left(-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\left(\dfrac{3}{5}+\dfrac{2}{7}+\dfrac{4}{35}\right)+\dfrac{1}{131}\)
\(=\dfrac{-9-2-7}{18}+\dfrac{21+10+4}{35}+\dfrac{1}{131}\)
=1/131
Bài 2:
b: \(B=\dfrac{1}{99}-\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{98\cdot99}\right)\)
\(=\dfrac{1}{99}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{98}-\dfrac{1}{99}\right)\)
\(=\dfrac{1}{99}-\dfrac{98}{99}=-\dfrac{97}{99}\)
Bài này mình làm xong rồi nhưng lỡ tay bấm nút hủy.
MONG CÁC BẠN
\(\frac{-1}{2}-\frac{-3}{5}+\frac{-1}{9}+\frac{1}{131}-\frac{-2}{7}+\frac{4}{35}-\frac{7}{18}\)
\(=\frac{-1}{2}+\frac{3}{5}-\frac{1}{9}+\frac{1}{131}+\frac{2}{7}+\frac{4}{35}-\frac{7}{18}\)
\(=\frac{1}{10}-\frac{122}{1179}+\frac{2}{5}-\frac{7}{18}\)
\(=-\frac{41}{11790}+\frac{1}{90}\)
\(=\frac{1}{131}\)
học tốt
bt làm r