1027 - 27 . { { ( 4 3 - 19 ) 2 : 25 + 9 } : 9 }
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a, 249 - 25 × 8 + 32 × 4
= 249 - 200 + 9 × 4
= 49 + 36
= 85
b,27 : { 480 : [(513 : 9 + 19 ) + 84 ]}
= 27 : { 480 : [(57 + 19) + 84 ]}
= 27 : { 480 : [76 + 84]}
= 27 : { 480 : 160}
= 27 : 3
= 9
c. 73 × 25 + 28 × 25 - 25
= 73 × 25 + 28 × 25 - 25 × 1
= 25 × (73 + 28 - 1)
= 25 × 100
= 2500
d. 2× 9 × 50 - 890
= (2 × 50) × 9 - 1
= 100 × 9 - 1
= 900 - 1
= 899
a)\(249-25\cdot8+3^2\cdot4\)
\(=249-200+9\cdot4\)
\(=49+36=85\)
b)\(27:\left\{480:\left[\left(513:9+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[\left(57+19\right)+84\right]\right\}\)
\(=27:\left\{480:\left[76+84\right]\right\}\)
\(=27:\left\{480:160\right\}\)
\(=27:3=9\)
c)\(73\cdot25+28\cdot25-25\)
\(=73\cdot25+28\cdot25-25\cdot1\)
\(=\left(73+28-1\right)\cdot25\)
\(=100\cdot25=2500\)
d)\(2\cdot9\cdot50-89^0\)
\(=2\cdot9\cdot50-1\)
\(=900-1=899\)
a) \(17-\left(-9\right)-27-19\\ =17+9-27-19\\ =\left(17-27\right)+\left(9-19\right)\\ =\left(-10\right)+\left(-10\right)=-20\)
b) \(3\cdot\left(-9\right)+9\\ =\left(-3\right)\cdot9+9\\ =9\left(-3+1\right)\\ =9\cdot\left(-2\right)=-18\)
c) \(-\left(-24\right)+\left(-37\right)-25+14\\ =24-37-25+14\\ =\left(24+14\right)-\left(37+25\right)\\ =38-62=-24\)
d) \(\left(-7\right)\cdot5-9\cdot\left(-4\right)-105\\ =\left(-7\right)\cdot5-9\cdot\left(-4\right)-21\cdot5\\ =5\left(-7-21\right)-\left(-36\right)\\ =5\cdot\left(-28\right)+36\\ =-140+36=-104\)
e) \(\left(-7\right)^2+32\div\left(-8\right)\\ =49+\left(-4\right)\\ =45\)
f) \(\left(-2\right)^2-36\div\left(-6\right)-\left|-7\right|\\ =4-\left(-6\right)-7\\ =4+6-7\\ =10-7=3\)
1: =-2/9(15/17+2/17)=-2/9
2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)
=-2-7/30=-67/30
3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
1: =-2/9(15/17+2/17)=-2/9
2: =−63+−2190=−63+−2190
=-2-7/30=-67/30
3: =34⋅75+97⋅32=34⋅75+97⋅32
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
a: Ta có: \(\left(8\cdot5^7+5^6-5^5\right):5^5\)
\(=8\cdot5^2+5-1\)
\(=200+4=204\)
b: Ta có: \(\left(9^{30}-27^{19}\right):3^{57}+\left(125^9-25^{12}\right):5^{24}\)
\(=3^{60}:3^{57}-3^{57}:3^{57}+5^{27}:5^{24}-5^{24}:5^{24}\)
\(=27-1+125-1\)
=150
a. (8,57 - 55 + 56) : 55
= (8,57 : 55) - (55 : 55) + (56 : 55)
= 1,72 - 1 + 5
= 2,89 - 1 + 5
= 6,89
b. (930 - 2719) : 357 + (1259 - 2512) : 524
= (930 : 357) - (2719 : 357) + (1259 : 524) - (2512 : 524)
= 33 - 1 + 125 - 1
= 27 - 1 + 125 - 1
= 150
c. (1012 + 511 . 29 - 513 - 28) : 4 . 55 . 106
= (1012 + 2,5 , 1010 - 513 - 28) : 1,25 . 1010
= (1012 : 1,25 . 1010) + (2,5 . 1010 : 1,25 . 1010) - (513 : 1,25 . 1010) - (28 : 1,25 . 1010)
= 80 + 2 - \(\dfrac{25}{256}\) - \(\dfrac{1}{48828125}\)
= 81,90234373 \(\approx\) 82
a)\(=\dfrac{3}{3}+\dfrac{4}{3}=\dfrac{7}{3}\)
b)\(=\dfrac{5}{9}\times\dfrac{3}{2}=\dfrac{15}{18}=\dfrac{5}{6}\)
d)\(=\left(\dfrac{12}{8}-\dfrac{3}{8}\right)\times2=\dfrac{9}{8}\times2=\dfrac{18}{8}=\dfrac{9}{4}\)
c)\(=\dfrac{4}{3}-\dfrac{5}{6}=\dfrac{8}{6}-\dfrac{5}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)
a) 1 + 4/3 = 7/3
b) 5/9 : 2/3 = 5/6
c ) 4/3 -1/3 x 5/2
= 1 x 5/2
= 5/2
d) ( 3/2 - 3/8) : 1/2
= 9/8 : 1/2
= 9/4
e) 15/16 : 3/8 x 3/4
= 5/2 x 3/4
= 15/8
f) 7/19 x 1/3 x 7/19 x 2/3
= 7/19 x (1/3 x 2/3)
= 7/19 x 2/9
= 14/171
g) 3/5 x 8/27 x 25/3
= 3/5 x 25/3 x 8/27
= 5 x 8/27
= 40/27
h) 1/5 + 4/11 + 4/5 + 7/11
= (1/5 + 4/5) + (4/11 + 7/11)
= 1 + 1
= 2
\(A=\dfrac{9}{8}-\dfrac{8}{9}+\dfrac{3}{24}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{19}{25}-\dfrac{1}{9}+\dfrac{2}{25}-\dfrac{1}{81}\)
\(=\dfrac{9}{8}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{1}{8}-\dfrac{8}{9}-\dfrac{1}{9}-\dfrac{1}{81}+\dfrac{19}{25}+\dfrac{2}{25}\)
\(=\dfrac{10}{8}+\dfrac{1}{4}-\dfrac{5}{16}-1-\dfrac{1}{81}+\dfrac{21}{25}\)
\(=\dfrac{20+4-5}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{19}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{32891}{16\cdot81\cdot25}\)
b: \(B=-\dfrac{1}{3}-\dfrac{8}{35}-\dfrac{2}{9}-\dfrac{1}{35}+\dfrac{4}{5}-\dfrac{4}{9}+\dfrac{3}{7}\)
\(=\dfrac{-1}{3}-\dfrac{2}{9}-\dfrac{4}{9}-\dfrac{8}{35}-\dfrac{1}{35}+\dfrac{4}{5}+\dfrac{3}{7}\)
\(=\dfrac{-3-2-4}{9}+\dfrac{-9}{35}+\dfrac{28+15}{35}\)
\(=-1+\dfrac{-9+43}{35}=-1+\dfrac{34}{35}=-\dfrac{1}{35}\)
1027 - 27 . { [ ( 43 - 19 )2 : 25 + 9 ] : 9 }
= 1000 . { [ 452 : 25 + 9 ] : 9 }
= 1000 . { 90 : 9 }
= 1000 . 10
= 100
p/s : dấu { } thứ 2 bạn nên thay = [ ] nhé !
Wen ơi bn ấn nhầm r
1000 . 10 = 10 000 nhé
Dù sao cx nên k bạn vài cái vì sự cố gắng làm bài :))