Từ Na2O , CaO , H2O và các dd CuSO4 , FeCl3 . Hãy viết các PTHH điều chế các hiđroxit tương ứng .
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Bài 2:
\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
\(Ca\left(OH\right)_2+Na_2CO_3\rightarrow CaCO_3\downarrow+2NaOH\)
Bài 3
a)
\(Na_2O+H_2O\rightarrow2NaOH\)
b)
\(BaO+H_2O\rightarrow Ba\left(OH\right)_2\)
c)
\(2NaOH+CuSO_4\rightarrow Na_2SO_4+Cu\left(OH\right)_2\downarrow\)
\(Na_2SO_4+Ba\left(OH\right)_2\rightarrow BaSO_4\downarrow+2NaOH\)
d)
\(2NaOH+CuSO_4\rightarrow Cu\left(OH\right)_2\downarrow+Na_2SO_4\)
e)
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2\downarrow+2NaCl\)
\(2KClO_3\rightarrow\left(t^o,MnO_2\right)2KCl+3O_2\)
\(2SO_2+O_2\rightarrow\left(t^o,V_2O_5\right)2SO_3\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(2K+2H_2O\rightarrow2KOH+H_2\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
a)
$2Na + 2H_2O \to 2NaOH + H_2$
$Na_2O + H_2O \to 2NaOH$
$Na_2CO_3 + Ca(OH)_2 \to CaCO_3 + 2NaOH$
$BaO + H_2O \to Ba(OH)_2$
$Ba(OH)_2 + Na_2CO_3 \to BaCO_3 + 2NaOH$
b)
$CuO + 2HCl \to CuCl_2 + H_2O$
$CuCl_2 + 2NaOH \to Cu(OH)_2 + 2NaCl$
$CuCl_2 + Ca(OH)_2 \to Cu(OH)_2 + CaCl_2$
$CuSO_4 + 2NaOH \to Cu(OH)_2 + Na_2SO_4$
$CuSO_4 + Ca(OH)_2 \to CaSO_4 + Cu(OH)_2$
$Cu(NO_3)_2 + 2NaOH \to Cu(OH)_2 + 2NaNO_3$
$Cu(NO_3)_2 + Ca(OH)_2 \to Ca(NO_3)_2 + Cu(OH)_2$
a)
2Na+2H2O→2NaOH+H22Na+2H2O→2NaOH+H2
Na2O+H2O→2NaOHNa2O+H2O→2NaOH
Na2CO3+Ca(OH)2→CaCO3+2NaOHNa2CO3+Ca(OH)2→CaCO3+2NaOH
BaO+H2O→Ba(OH)2BaO+H2O→Ba(OH)2
Ba(OH)2+Na2CO3→BaCO3+2NaOHBa(OH)2+Na2CO3→BaCO3+2NaOH
b)
CuO+2HCl→CuCl2+H2OCuO+2HCl→CuCl2+H2O
CuCl2+2NaOH→Cu(OH)2+2NaClCuCl2+2NaOH→Cu(OH)2+2NaCl
CuCl2+Ca(OH)2→Cu(OH)2+CaCl2CuCl2+Ca(OH)2→Cu(OH)2+CaCl2
CuSO4+2NaOH→Cu(OH)2+Na2SO4CuSO4+2NaOH→Cu(OH)2+Na2SO4
CuSO4+Ca(OH)2→CaSO4+Cu(OH)2CuSO4+Ca(OH)2→CaSO4+Cu(OH)2
Cu(NO3)2+2NaOH→Cu(OH)2+2NaNO3Cu(NO3)2+2NaOH→Cu(OH)2+2NaNO3
Cu(NO3)2+Ca(OH)2→Ca(NO3)2+Cu(OH)2
Bài 1
a) Fe+2HCl\(\rightarrow\)FeCl2+H2
b) Cu(OH)2+2HCl\(\rightarrow\)CuCl2+2H2O
c) Na2CO3+2HCl\(\rightarrow\)NaCl+CO2+H2O
d) Fe+CuCl2\(\rightarrow\)FeCl2+Cu
Bài 2:
CaO+H2O\(\rightarrow\)Ca(OH)2
Ca(OH)2+Na2CO3\(\rightarrow\)CaCO3+2NaOH
- Điều chế H2SO4:
\(2SO_2+O_2\underrightarrow{to,xt}2SO_3\\ SO_3+H_2O\rightarrow H_2SO_4\)
- Đ/chế CO2:
\(BaCO_3\underrightarrow{^{to}}BaO+CO_2\)
- Đ/chế Cu(OH)2
\(Na_2O+H_2O\rightarrow2NaOH\\ CuO+H_2SO_{4\left(đ.chế\right)}\rightarrow CuSO_4+H_2O\\ CuSO_4+2NaOH\rightarrow Cu\left(OH\right)_2+Na_2SO_4\)
\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
\(Na_2O+H_2O\rightarrow2NaOH\)
\(\rightarrow\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
F e 2 O 3 + 6 H C l → 2 F e C l 3 + 3 H 2 O
N a 2 O + H 2 O → 2 N a O H
F e C l 3 + 3 N a O H → F e ( O H ) 3 + 3 N a C l
Na2O + H2O \(\rightarrow\) 2NaOH
CaO + H2O \(\rightarrow\) Ca(OH)2
CuSO4 + 2NaOH \(\rightarrow\) Cu(OH)2 + Na2SO4
Ca(OH)2 + CuSO4 \(\rightarrow\) Cu(OH)2 + CaSO4
FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaCl
3Ca(OH)2 + 2FeCl3 \(\rightarrow\) 2Fe(OH)3 + 3CaCl2
í bn là điều chế các bazơ tương ứng hã