1, Rút gọn :
a) \(\dfrac{2.4}{6.18}\) ; b) \(\dfrac{3.5.7}{6.9.14}\) ; c) \(\dfrac{4.7-4.5}{64}\)
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\(\frac{2.4}{6.18}=\frac{2.2.2}{2.3.3.2.3}=\frac{2}{7}\)
mk đã làm xog, đúng tk cho mk
\(=\dfrac{6\cdot18}{12\cdot48}=\dfrac{6}{12}\cdot\dfrac{18}{48}=\dfrac{1}{2}\cdot\dfrac{3}{8}=\dfrac{3}{16}\)
\(\frac{2.4}{6.18}=\frac{1.2}{3.9}=\frac{2}{27}\)
\(\frac{3.5.7}{6.9.14}=\frac{1.5.7}{2.9.2}=\frac{35}{36}\)
\(\frac{4.7-4.5}{64}=\frac{4\left(7-5\right)}{64}=\frac{8}{64}=\frac{1}{8}\)
a)\(\frac{2.4}{6.18}\)=\(\frac{2.2.2}{2.3.2.3.3}\)=\(\frac{2.1.1}{1.3.1.3.3}\)=\(\frac{2}{27}\)
b)\(\frac{3.5.7}{6.9.14}\)=\(\frac{3.5.7}{2.3.3.3.2.7}\)=\(\frac{1.5.1}{2.1.3.3.2.1}\)=\(\frac{5}{36}\)
c)\(\frac{4.7-4.5}{64}\)=\(\frac{4.\left(7-5\right)}{64}\)=\(\frac{4.2}{64}\)=\(\frac{8}{64}\)=\(\frac{1}{8}\)
1) Các phân số tối giản là: \(\frac{1}{5};\frac{5}{7};\frac{-2}{9}\)
2) a) \(\frac{28}{36}=\frac{28:4}{36:4}=\frac{7}{9}\)
b) \(\frac{-63}{90}=\frac{-63:9}{90:9}=\frac{-7}{10}\)
c) \(\frac{40}{-120}=\frac{40:40}{-120:40}=\frac{-1}{3}\)
3) a) \(\frac{2.4}{6.18}=\frac{2.2.2}{2.3.3.2.3}=\frac{2}{27}\)
b) \(\frac{3.5.7}{6.9.14}=\frac{3.5.7}{2.3.9.2.7}=\frac{5}{36}\)
c) \(\frac{4.7-4.5}{64}=\frac{4.\left(7-5\right)}{64}=\frac{4.2}{64}=\frac{8}{64}=\frac{1}{8}\)
4) Muốn rút gọn một phân số chưa tối giản, ta tìm ƯCLN của cả hai số ở tử và mẫu, rồi cùng đem cả tử và mẫu chia cho số chung vừa tìm được.
\(\frac{2.4}{6.18}=\frac{1.2}{3.9}=\frac{2}{27}\)
\(\frac{2.4}{6.18}=\frac{8}{108}=\frac{2}{27}\)
Xét tử: 2.4+4.8+8.12+12.16+16.20 = 2.1.2.2 + 2.2.2.4 + 2.2.4.6 + 2.2.6.8 + 2.2.8.10
= 2.2.(1.2+2.4+4.6+6.8+8.10)
=> 2.4+4.8+8.12+12.16+16.20/1.2+2.4+4.6+6.8+8.10 = 2.2.(1.2+2.4+4.6+6.8+8.10) / 1.2+2.4+4.6+6.8+8.10
= 2.2 = 4
a) \(\dfrac{3-\sqrt{x}}{x-9}=\dfrac{-\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=-\dfrac{1}{\sqrt{x+3}}\)(\(x\ge0,x\ne9\))
b) \(\dfrac{x-5\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}-2\right)}{\sqrt{x}-3}=\sqrt{x}-2\left(x\ge0,x\ne9\right)\)
a) \(\dfrac{3-\sqrt{x}}{x-9}=\dfrac{3-\sqrt{x}}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=-\dfrac{1}{\sqrt{x}+3}\)
b) \(\dfrac{x-5\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}{\sqrt{x}-3}=\sqrt{x}-2\)
c) \(6-2x-\sqrt{9-6x+x^2}=6-2x-\sqrt{\left(3-x\right)^2}=6-2x-\left|3-x\right|\)
mà \(x< 3\Rightarrow3-x>0\Rightarrow6-2x-\left|3-x\right|=6-2x-3+x=3-x\)
a, \(\dfrac{2.4}{6.18}\)=\(\dfrac{2}{27}\)
b,\(\dfrac{3.5.7}{6.9.14}\)=\(\dfrac{105}{756}\)=\(\dfrac{35}{232}\)
c,\(\dfrac{4.7-4.5}{64}\)=\(\dfrac{28-20}{64}\)=\(\dfrac{8}{64}\)=\(\dfrac{1}{8}\)
nhớ like nhé
\(\dfrac{2.4}{6.18}=\dfrac{8}{108}=\dfrac{2}{27}\)
\(\dfrac{3.5.7}{6.9.14}=\dfrac{105}{756}=\dfrac{35}{252}\)
\(\dfrac{4.7-4.5}{64}=\dfrac{4.\left(7-5\right)}{64}=\dfrac{4.2}{64}=\dfrac{8}{64}=\dfrac{1}{8}\)
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