Giải giúp mình bài này với!! Cảm mơn các bạn nhiều lắmm
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a: ĐKXĐ x>0; x<>1
\(A=\dfrac{x-1}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\sqrt{x}-1}{1}=\dfrac{x-1}{\sqrt{x}}\)
b: A<0
=>x-1<0
=>0<x<1
a) nCuCl2 = 0,15.2 = 0,3 (mol)
PTHH: 2Al + 3CuCl2 --> 2AlCl3 + 3Cu
____0,2<------0,3--------->0,2---->0,3
=> m = 0,3.64 - 0,2.27 = 13,8 (g)
b) \(C_{M\left(AlCl_3\right)}=\dfrac{0,2}{0,15}=1,3333M\)
She thanks me for inviting her to the party.
Why's Mr.Grim sitting in a boat and fishing?
Do your classmates do their homework in the library?
Kate is going to tell her younger sister about her trip to Japan.
My sister loves taking care of small animals.
She thanks me for inviting her to the party.
Why's Mr. Grim interested in sitting in a boat and fishing?
Do your classmates do their homework in the library?
Kate is going to tell her younger sister about her trip to Japan
My sister loves taking care of small animals
tham khảo :
1.His illness was ________ than we had thought at first.
A. much serious
B. more serious
C. serious
D. most serious
2. Nam is _______ in his class.
A. taller
B. the most tall
C. the tallest
D. more tall
3. Traveling by plane is _______ than traveling by car.
A. fast
B. more fast
C. the most fast
D. faster
4. Actually, today I feel ______ than I did yesterday.
A. the worst
B. worst
C. worse
D. bad
5. Could you speak Vietnamese _______ than, so I can understand what you mean?
A. more clearly
B. clearly
C. the most clearly
D. the clearest
6. That flight ticket is _________ of all.
A. expensive
B. the most expensive
C. more expensive
D. the expensive
7. Phong works ________ than most of him friends.
A. a lot more hardly
B. more hardly
C. many harder
D. much harder
8. I tried to spend ______ money.
A. little
B. less
C. the least
D. the less than
9. My friend is much _______ than me.
A. prettier
B. pretty
C. the prettiest
D. more prettier
10. My mom speaks Korean ______ I do.
A. fluently
B. more fluently than
C. more fluently
D. most fluently
\(x=\sqrt{9+4\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)
\(=\sqrt{\left(\sqrt{5}+2\right)^2}-\sqrt{\left(\sqrt{5}-2\right)^2}\)
\(=\left|\sqrt{5}+2\right|-\left|\sqrt{5}-2\right|\)
\(=\sqrt{5}+2-\sqrt{5}+2=4\)
\(y=\sqrt{3+2\sqrt{5}}-\sqrt{3-2\sqrt{5}}\)
Xem lại đề, \(\sqrt{3-2\sqrt{5}}\) không xác định.