Tìm x,biết:
a,96-3(x+1)=42
b,12x - 33=32 . 33
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Tìm x:
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 -1
x = 17
b, 12x - 33 = 32.33
12x - 33 =9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x=276:12
x=23
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
b, 12x - 33 = 32 . 33
12x - 33 = 9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
a: Ta có: \(7x+25=144\)
\(\Leftrightarrow7x=119\)
hay x=17
b: Ta có: \(33-12x=9\)
\(\Leftrightarrow12x=24\)
hay x=2
c: Ta có: \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
hay x=31
d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)
\(\Leftrightarrow5\left(726-3x\right)=2175\)
\(\Leftrightarrow726-3x=435\)
\(\Leftrightarrow3x=291\)
hay x=97
e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x+5\right)=18\)
\(\Leftrightarrow2x+5=23\)
\(\Leftrightarrow2x=18\)
hay x=9
96 - 3( x + 1 ) = 42
3( x + 1 ) = 96 - 42
3( x + 1 ) = 54
x + 1 = 54 : 3 = 18
x = 18 - 1
x = 17
cau 1
96-3(x+1)=42
=> 3(x-1)=54
=> x-1=18
=> x=19
cau 2
12x-33=32.33
=> 12x-33=243
=> 12x=276
=> x=23
Bài 2:
a: Ta có: \(2^{x+1}\cdot3^y=12^x\)
\(\Leftrightarrow2^{x+1}\cdot3^y=2^{2x}\cdot3^x\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\x=y\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)
a ) 5(x + 35 ) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
a) x+35=515:5
x+35=103
x= 103-35=68
b) 96-3(x+1)=42
3(x+1)=96-42=54
x+1=54:3=18
x=18-1=17
c) 12x-33=32.33
12x - 33 = 9 . 27
12x - 33=243
12x = 243 +33
12x = 276
x= 276:12
x=23
a) 5 ( x + 35 ) = 515
x + 35 = 103
x = 68
b) 96 - 3(x+1) = 49
3(x+1) = 47
x + 1 = 47/3
x = 44/3
c) 12x - 33 = 3^2 * 3^3
12x - 33 = 243
12x = 276
x = 23
5 ( x + 35 ) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
96 - 3( x + 1 ) = 49
3( x + 1 ) = 96 - 49
3( x + 1 ) = 47
x + 1 = 47/3
x = 47/3 - 1
x = 44/3
12x - 33 = 32 . 33
12x - 33 = 35
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
(2-x)^3+(2+x)^3-12x(x+1)=0
=>\(8-12x+6x^2-x^3+8+12x+6x^2+x^3-12x\left(x+1\right)=0\)
=>\(12x^2+16-12x^2-12x=0\)
=>16-12x=0
=>4-3x=0
=>x=4/3
a, 96 - 3(x + 1 ) = 42
3( x+ 1 ) = 54
x + 1 = 18
x = 17
b , 12x - 33 = 32 . 33
12x - 33 = 35
12x-33 = 243
12 x= 276
x = 23
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