210.13 + 210. 65 / 28. 104
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`@` `\text {Ans}`
`\downarrow`
`A)`
`37 \times 46+37 \times 51+111`
`= 37 \times (46+51)+111`
`= 37 \times 97+111`
`= 3589 +111`
`= 3700`
`B)`
`35 \times 215-35 \times 210-175`
`= 35 \times (215-210)-175`
`= 35 \times 5-175`
`= 175-175=0`
`E)`
`76 \times 102-76 \times 2`
`= 76 \times (102-2)`
`= 76 \times 100`
`= 7600`
`C)`
`85 \times 94+85 \times 2 +170 \times 2`
`= 85 \times (94+2) + 170 \times 2`
`= 85 \times 96+170 \times 2`
`= 8160+340`
`= 8500`
`48 \times 56+28 \times 104`
`= 48 \times 28 \times 2+28 \times 104`
`= 28 \times (48 \times 2+104)`
`= 28 \times (96+104)`
`= 28 \times 200`
`= 5600`
`G)`
`206 \times 12-206-206`
`= 206 \times (12-1-1)`
`= 206 \times 10`
`= 2060`
a) 37 x 46 + 37 x 51 + 111
= 37 x ( 46 + 51 ) + 111
= 37 x 97 + 111
= 3589 + 111
= 3700
b) 35 x 215 - 35 x 210 - 175
= 35 x ( 215 - 210 ) - 175
= 35 x 5 - 175
= 175 - 175
= 0
e) 76 x 102 - 76 x 2
= 76 x ( 102 - 2 )
= 76 x 100
= 7600
c) 85 x 94 + 95 x 2 + 170 x 2
= 7990 + 2 x ( 95 + 170 )
= 7990 + 2 x 265
= 7990 + 530
= 8520
48 x 56 + 28 x 104
= 2688 + 2912
= 5600
g) 206 x 12 - 206 - 206
= 2472 - 206 - 206
= 2266 - 206
= 2060
B=C*[13*37*(5*3-15)]=0
\(A=\dfrac{2^{10}\cdot78}{2^8\cdot26\cdot4}=\dfrac{78}{26}=3\)
= 2^10.(13+65) / 2^8.2^3.13
= 2^10.78 / 2^11.13
= 2^10.3.13 / 2^11.13
= 2^11.3.13 / 2^11.13
= 3
k mk nha
\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{47}\\{43}\end{array}}\\\hline{\,\,\,90}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{43}\\{47}\end{array}}\\\hline{\,\,\,90}\end{array}\)
\(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{65}\\{28}\end{array}}\\\hline{\,\,\,\,93}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{28}\\{65}\end{array}}\\\hline{\,\,\,93}\end{array}\)
\(\dfrac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}=\dfrac{2^{10}\cdot\left(13+65\right)}{2^8\cdot104}=\dfrac{2^{10}\cdot78}{2^8\cdot104}=\dfrac{2^2\cdot3}{4}=3\)
2^10 . ( 13 + 65 ) / 2^8 . 104
2^10 . 78 / 2^8 . 104
= 2^8 . 2^2 . 78 / 2^8 . 104
= 2^2 . 78 / 104
= 4 . 78 / 104
= 78 / 26
= 3
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