tính nhanh a.\(\dfrac{19.3-19.4+19}{1995.1996.1997}\)
b.\(\dfrac{48.48-17}{48.48+31}\)
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SI
4
TM
15 tháng 7 2017
2. \(54^{49}+54^{48}=54^{48}\left(54+1\right)=54.55=54.5.11\) chia hết cho 5 và 11
3.
+)Xét x=3k => (x+12)(x+20)(x+34)=(3k+12)(3x+20)(3k+34)=3(k+4)(3k+20)(3k+34) chia hết cho 3
+)Xét x=3k+1=>(x+12)(x+20)(x+34)=(3k+13)(3k+21)(3k+35)=(3k+13)3(k+7)(3k+35) chia hết cho 3
+)Xét x=3k+2=>(x+12)(x+20)(x+34)=(3k+14)(3k+22)(3k+36)=(3k+14)(3k+22)3(k+12) chia hết cho 3
Từ 3 trường hợp trên suy ra đpcm
MN
9 tháng 5 2021
\(a.\)
\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)
\(b.\)
\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)
\(c.\)
\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)
9 tháng 5 2021
a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\)
b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\)
c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)
12 tháng 12 2021
\(a,\dfrac{3}{5}+\dfrac{1}{5}.\dfrac{-17}{9}=\dfrac{3}{5}-\dfrac{17}{45}=\dfrac{27}{45}-\dfrac{17}{45}=\dfrac{10}{45}=\dfrac{2}{9}\\ b,\left(-\dfrac{4}{15}-\dfrac{18}{19}\right)-\left(\dfrac{20}{19}+\dfrac{11}{15}\right)=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=\left(-\dfrac{4}{15}-\dfrac{11}{15}\right)-\left(\dfrac{18}{19}+\dfrac{20}{19}\right)=-1-2=-3\)
12 tháng 12 2021
\(a,=\dfrac{3}{5}+\left(-\dfrac{17}{45}\right)=\dfrac{2}{9}\)
\(b,=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=-3\)
20 tháng 9 2015
C=2.2+4.4+6.6+...+48.48
C=2.(4-2)+4.(6-2)+6.(8-2)+...+48.(50-2)
C=2.4-2.2+4.6-4.2+6.8-6.2+...+48.50-48.2
C=(2.4+4.6+6.8+...+48.50)-(2.2+4.2+6.2+...+48.2)
Đặt D=2.4+4.6+6.8+...+48.50
6D=2.4.6+4.6.6+6.8.6+...+48.50.6
6D=2.4.6+4.6.(8-2)+6.8.(10-4)+...+48.50.(52-46)
6D=2.4.6+4.6.8-2.4.6+6.8.10-4.6.8+...+48.50.52-46.48.50
6D=48.50.52
D=20800
ĐặtE=2.2+4.2+6.2+...+48.2
E=(2+4+6+...+48).2
đến đấy rồi bạn tình tổng 2+4+6+...+48 rồi bạn tự làm tiếp nhé
nhớ tick cho mình.Thanks bạn
VT
3
IW
16 tháng 5 2016
Ta có: 24.24+28.28+48.48
= 24.24+(24+4).(24+4)+(24+24).(24+24)
=24.24+24.24+4.24+24.4+4.4+24.24+24.24+24.24+24.24
= ( 24.24+24.24+24.24+24.24+24.24+24.24)+4.24+4.24+4.4
= 6(24.24)+24.8+4.4
= (6.24+6.24+24.8)+4.4
= 24.20+4.4
= 4.6.4.5+4.4
= 4.4(6.5+1)
= 16.(30+1)
= 16.31
16 tháng 5 2016
Ta có: 24.24+28.28+48.48
= 24.24+(24+4).(24+4)+(24+24).(24+24)
=24.24+24.24+4.24+24.4+4.4+24.24+24.24+24.24+24.24
= ( 24.24+24.24+24.24+24.24+24.24+24.24)+4.24+4.24+4.4
= 6(24.24)+24.8+4.4
= (6.24+6.24+24.8)+4.4
= 24.20+4.4
= 4.6.4.5+4.4
= 4.4(6.5+1)
= 16.(30+1)
= 16.31
a.\(\dfrac{19\left(3-4+1\right)}{1995.1996.1997}\)=\(\dfrac{19.0}{1995.1996.1997}\)=0
\(A=\dfrac{19.3-19.4+19}{1995.1996.1997}=\dfrac{19.3-19.4+19.1}{1995.1996.1997}=\dfrac{19.0}{1995.1996.1997}=\dfrac{0}{1995.1996.1997}=0\)b) sửa đề:
\(B=\dfrac{48.48-17}{47.48+31}=\dfrac{48.\left(47+1\right)-17}{47.48+31}=\dfrac{48.47+48-17}{47.48+31}=\dfrac{47.48+31}{47.48+31}=1\)