Mọi người ơi ! Giúp em với ạ ( Đầu bài là : điền kết quả tính đc vào bảng ) . Em camon trc nhoa !
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Câu b
5x-8=2x+7
<=> 3x=7+8=15
<=>x=5
Câu c:
<=>4x=3+5
<=>4x=8
<=>x=2
Câu d
<=>6=4x
<=> x=3/2
Câu e
<=> 2x+8-6x+15=3
<=>4x=20
<=>x=5
b)5x-8=2x+7
⇔3x=15
⇔ x=5
c)4x2+2x-5=4x2-2x+3
⇔ 4x=8
⇔ x=2
d)2x3-3x+6=2x3+x
⇔ 4x=6
⇔ \(x=\dfrac{3}{2}\)
e)2(x+4)-3(2x-5)=3
⇔ 2x+4-6x+15=3
⇔ -4x+19=3
⇔ 4x=16
⇔ x=4
2 He was writing a report
3 Tom was calling the employers at 8 o'clock yesterday morning
4 I was decorating my house when you came
5 My sister was eating a chocolate cake
6 I was doing my exercuse at 6 o'clock yesterday morning
7 I was writing a report when my friend called
8 Tom was taking a photo of mine when I was eating
Câu 2.
\(C=\dfrac{N}{20}=\dfrac{4080}{20}=204\)(chu kì)
\(L=\dfrac{N}{2}\cdot3,4=\dfrac{4080}{2}\cdot3,4=6936A^o\)
\(G=X=30\%\cdot4080=1224nu\)
\(A=T=\dfrac{4080-2\cdot1224}{2}=816nu\)
uses crt;
var m:integer;
begin
clrscr;
write('Nhap m='); readln(m);
if m mod 2=0 then writeln(m,' la so chan')
else writeln(m,' la so le');
writeln('Binh phuong cua ',m,' la: ',sqr(m));
writeln('Can bac hai cua ',m,' la: ',sqrt(m));
writeln('Gia tri tuyet doi cua ',m,' la: ',abs(m));
readln;
end.
6:
\(2^{225}=\left(2^3\right)^{75}=8^{75}\)
\(3^{150}=\left(3^2\right)^{75}=9^{75}\)
mà 8<9
nên \(2^{225}< 3^{150}\)
4: \(\left|5x+3\right|>=0\forall x\)
=>\(-\left|5x+3\right|< =0\forall x\)
=>\(-\left|5x+3\right|+5< =5\forall x\)
Dấu = xảy ra khi 5x+3=0
=>x=-3/5
1:
\(\left(2x+1\right)^4>=0\)
=>\(\left(2x+1\right)^4+2>=2\)
=>\(M=\dfrac{3}{\left(2x+1\right)^4+2}< =\dfrac{3}{2}\)
Dấu = xảy ra khi 2x+1=0
=>x=-1/2
Thay số vào mà nhấn máy tính:
1.= -1008
2.= -1
3.= 9
4.= \(\dfrac{-133}{64}\)