tính nhanh
121212 / 151515 + 121212 / 353535 + 121212 / 636363 + 121212 / 999999
K
Khách
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Những câu hỏi liên quan
H9
HT.Phong (9A5)
CTVHS
9 tháng 4 2023
\(\dfrac{121212}{353535}+-\dfrac{2323}{4242}\)
\(=\dfrac{12}{35}+-\dfrac{23}{42}\)
\(=-\dfrac{43}{210}\)
9 tháng 4 2023
\(=\dfrac{12}{35}-\dfrac{23}{42}=\dfrac{72-115}{210}=\dfrac{-43}{210}\)
21 tháng 3 2019
\(\left(\frac{151515}{60606}+\frac{151515}{121212}+\frac{151515}{202020}+\frac{151515}{303030}+\frac{151515}{242424}\right)\cdot\frac{28}{12}\)
\(=\left(\frac{5}{2}+\frac{5}{4}+\frac{3}{4}+\frac{1}{2}+\frac{5}{8}\right)\cdot\frac{28}{12}\)
\(=\left[\left(\frac{5}{2}+\frac{1}{2}\right)+\left(\frac{5}{4}+\frac{3}{4}\right)+\frac{5}{8}\right]\cdot\frac{28}{12}\)
\(=\left(3+2+\frac{5}{8}\right)\cdot\frac{28}{12}\)
\(=\left(5+\frac{5}{8}\right)\cdot\frac{28}{12}\)
\(=\frac{45}{8}\cdot\frac{28}{12}\)
\(=\frac{105}{8}\)
TT
0
DT
2
6 tháng 2 2016
131313/151515+131313/353535+131313/636363+131313/999999=13/15+13/35+13/63+13/99
=52/33=1/19/33
DUYỆT NHÉ
SP
2
Q
17 tháng 8 2016
= 13/15 + 13/35 + 13/63 + 13/99
= 13/ 3×5 + 13/5×7 + 13/7×9 + 13/9×11
= 13 x 1/2( 1/3 – 1/5 + 1/5 – 1/7 +1/7 – 1/9 +1/9 – 1/11)
= 13/2 x ( 1/3 – 1/11)
= 13/2 x 8/33 = 104/66=52/33
Q
17 tháng 8 2016
\(D=\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)
\(D=\frac{13}{3}\times5+\frac{13}{5}\times7+\frac{13}{7}\times9+\frac{13}{9}\times11\)
\(D=13\times\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(D=\frac{13}{2}\times\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(D=\frac{13}{2}\times\frac{8}{33}=\frac{104}{66}=\frac{52}{33}\)
\(D=\frac{52}{33}\)
S
1
7 tháng 6 2016
(131313/151515+ 131313/353535+131313/636363+131313/999999)*33
=(13/15+13/35+13/63+13/99)*33
=52/33*33
=52
ND
0
NM
3
5 tháng 5 2018
a) \(\frac{121212}{151515}+\frac{1414}{2121}=\frac{12}{15}+\frac{14}{21}=\frac{12}{15}+\frac{2}{3}=\frac{12}{15}+\frac{10}{15}=\frac{22}{15}\)
\(\frac{121212}{151515}+\frac{121212}{353535}+\frac{121212}{636363}+\frac{121212}{999999}\)
= \(\frac{12.10101}{15.10101}+\frac{12.10101}{35.10101}+\frac{12.10101}{63.10101}+\frac{12.10101}{99.10101}\)
= \(\frac{12}{15}+\frac{12}{35}+\frac{12}{63}+\frac{12}{99}\)
= \(\frac{12}{3.5}+\frac{12}{5.7}+\frac{12}{7.9}+\frac{12}{9.11}\)
= \(6.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
= \(6.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
= \(6.\left(\frac{1}{3}-\frac{1}{11}\right)\)
= \(6.\frac{8}{33}\)
= \(\frac{16}{11}\)