Tìm x, biết: 1,56 × X = X × 263
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1,56 x X = X x 263
=> 263 x X - 1,56 x X =0
=> X(263-1,56)=0
=> X x 261,44 =0
=> X = 0: 261,44
=> X =0
\(x=\frac{1,56\left(5\right)-2,65\left(6\right)}{3,6\left(5\right)}\)
\(x=\frac{1,56+0,00\left(5\right)-2,65-0,00\left(6\right)}{3,6+0,0\left(5\right)}\)
\(x=\frac{\frac{39}{25}+\frac{0,\left(5\right)}{100}-\frac{53}{20}-\frac{0,\left(6\right)}{100}}{\frac{18}{5}+\frac{0,\left(5\right)}{10}}\)
\(x=\frac{\frac{39}{25}+\frac{5}{9}:100-\frac{53}{20}-\frac{6}{9}:100}{\frac{18}{5}+\frac{5}{9}:10}\)
\(x=\frac{\frac{39}{25}+\frac{1}{180}-\frac{53}{20}-\frac{1}{150}}{\frac{18}{5}+\frac{1}{18}}\)
\(x=\frac{\frac{1404}{300}+\frac{5}{900}-\frac{2385}{900}-\frac{6}{900}}{\frac{324}{90}+\frac{5}{90}}\)
\(x=\frac{-982}{900}:\frac{329}{90}\)
\(x=\frac{-491}{450}.\frac{90}{329}=\frac{-491}{1645}\)
1) b) \(\frac{36}{x}=\frac{54}{3}\)
\(\Rightarrow54x=36.3\)
\(\Rightarrow54x=108\)
\(\Rightarrow x=\frac{108}{54}\)
\(\Rightarrow x=2\)
vay \(x=2\)
d) \(1,56:2,88=2,6:x\)
\(2,6:x=\frac{1,56}{2,88}\)
\(2,6:x=\frac{13}{24}\)
\(x=2,6:\frac{13}{24}\)
\(x=\frac{13}{5}.\frac{24}{13}\)
\(x=\frac{24}{5}\) hay \(x=4,8\)
vay \(x=4,8\)
a,\(\Rightarrow x:3=1,56+7,2\)
\(\Rightarrow x:3=8,76\)
\(\Rightarrow x=8,76\cdot3\)
\(\Rightarrow x=26,28\)
b,\(\Rightarrow x:6=1,248:4\)
\(\Rightarrow x:6=0,312\)
\(\Rightarrow x=0,312\cdot6\)
\(\Rightarrow x=1,872\)
c,(x+x+x+x+...+x)+(2+5+8+....+29)=165
10 số hạng 10 số hạng
\(\Rightarrow\)10x+(29+2)*10:2=165
\(\Rightarrow\)10x+155=165
\(\Rightarrow10x=165-155\)
\(\Rightarrow10x=10\)
\(\Rightarrow x=10:10\)
\(\Rightarrow x=1\)
x + 5,47 = 63,18 + 1,56
x + 5,47 = 64,74
x = 64,74 - 5,47
x = 59,27
105,8 - x = 2,47+ 5,6
105,8 - x = 8,07
x = 105,8 - 8,07
x = 97,73
x + 5,47 = 63,18 + 1,56
x + 5,47 = 64,74
x = 64,74 - 5,47
x = 59,27
Vậy x = 59,27
105,8 - x = 2,47 + 5,6
105,8 - x = 8,07
x = 105,8 - 8,07
x = 97,73
Vậy x = 97,73