\(\frac{3\cdot x-0.8}{x}+14.5=15\)
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a ) \(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(x\times1+x\times\frac{9}{6}+x\times\frac{7}{2}=252\)
\(x\times\left(1+\frac{9}{6}+\frac{7}{2}\right)=252\)
\(x\times6=252\)
\(x=252\div6\)
\(x=42\)
b ) \(\left(3\times x-0,8\right)\div x+14,5=15\)
\(\left(3\times x-0,8\right)\div x=15-14,5\)
\(\left(3\times x-0,8\right)\div x=0,5\)
\(0,8\div x=3-0,5\)
\(0,8\div x=2,5\)
\(x=0,8\div2,5\)
\(x=0,32\)
( 3 x - 0.8 ) : x + 14.5 = 15
( 3 x - 0.8 ) x \(\frac{1}{x}\)+ 14,5 = 15
3X x \(\frac{1}{x}\)- 0,8 x \(\frac{1}{x}\)= 0,5
\(\frac{3x}{x}-\frac{0,8}{x}=\frac{0,5x}{x}\)
=> 3x - 0,8 = 0,5x
3x - 0,5x = 0,8
2,5x = 0,8
x = 2,5 : 0,8
x = \(\frac{25}{8}=3,125\)
\(A=\left[0,8\cdot7+(0,8)^2\right]\cdot\left[1,25\cdot7-\frac{4}{5}\cdot1,25\right]-47,86\)
\(=0,8\cdot(7+0,8)\cdot1,25\cdot(7-0,8)-47,86\)
\(=0,8\cdot7,8\cdot1,25\cdot6,2-47,86\)
\(=48,36-47,86=0,5\)
\(B=\frac{(1,09-0,29)\cdot\frac{5}{4}}{(18,9-16,65)\cdot\frac{8}{9}}=\frac{0,8\cdot1,25}{2,25\cdot\frac{8}{9}}=\frac{1}{2}\)
\(A:B=0,5:\frac{1}{2}=\frac{1}{2}:\frac{1}{2}=\frac{1}{2}\cdot2=1\)
A gấp 1 lần B
\(\frac{3x-0.8}{x}+14.5=15\)
\(3-\frac{0.8}{x}=15-14.5\)
\(3-\frac{0.8}{x}=0.5\)
\(\frac{0.8}{x}=3-0.5\)
\(\frac{0.8}{x}=2.5\)
\(x=\frac{0.8}{2.5}=\frac{8}{25}\)
\(\frac{3\cdot x-0.8}{x}+14.5=15\)
\(\frac{3\cdot x-0.8}{x}=15-14.5\)
\(\frac{3\cdot x-0.8}{x}=\frac{1}{2}\)
\(2\cdot\left(3\cdot x-0.8\right)=x\cdot1\)
\(6\cdot x-1.6=x\)
\(6\cdot x-x=1.6\)
\(5\cdot x=1.6\)
\(x=1.6:5\)
\(x=0.32\)