Tính giá trị biểu thức :
\(\left[\frac{4}{5}+\frac{4}{10}\right]\times5-\frac{17}{5}.\)
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\(F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\right)\)
\(F=\frac{15}{14}-\frac{17}{23}+\frac{80}{87}-\frac{5}{4}+\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\)
\(F=\frac{15}{14}+\left(\frac{-17}{23}+\frac{17}{23}\right)+\left(\frac{-5}{4}+\frac{-15}{4}+\frac{1}{4}\right)+\frac{80}{87}\)
\(F=\frac{15}{14}+0+\frac{-19}{4}+\frac{80}{87}\)
\(\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{17}{23}-\frac{15}{4}+\frac{1}{4}\right)\)
\(=\frac{15}{14}-\frac{8561}{8004}+\left(-\frac{127}{46}\right)\)
\(=-2,759031199\)
a)
\(\begin{array}{l}A = \left( {2 + \frac{1}{3} - \frac{2}{5}} \right) - \left( {7 - \frac{3}{5} - \frac{4}{3}} \right) - \left( {\frac{1}{5} + \frac{5}{3} - 4} \right).\\A = \left( {\frac{{30}}{{15}} + \frac{5}{{15}} - \frac{6}{{15}}} \right) - \left( {\frac{{105}}{{15}} - \frac{9}{{15}} - \frac{{20}}{{15}}} \right) - \left( {\frac{3}{{15}} + \frac{{25}}{{15}} - \frac{{60}}{{15}}} \right)\\A = \frac{{29}}{{15}} - \frac{{76}}{{15}} - \left( {\frac{{ - 32}}{{15}}} \right)\\A = \frac{{29}}{{15}} - \frac{{76}}{{15}} + \frac{{32}}{{15}}\\A = \frac{{ - 15}}{{15}}\\A = - 1\end{array}\)
b)
\(\begin{array}{l}A = \left( {2 + \frac{1}{3} - \frac{2}{5}} \right) - \left( {7 - \frac{3}{5} - \frac{4}{3}} \right) - \left( {\frac{1}{5} + \frac{5}{3} - 4} \right)\\A = 2 + \frac{1}{3} - \frac{2}{5} - 7 + \frac{3}{5} + \frac{4}{3} - \frac{1}{5} - \frac{5}{3} + 4\\A = \left( {2 - 7 + 4} \right) + \left( {\frac{1}{3} + \frac{4}{3} - \frac{5}{3}} \right) + \left( { - \frac{2}{5} + \frac{3}{5} - \frac{1}{5}} \right)\\A = - 1 + 0 + 0 = - 1\end{array}\)
\(=8\frac{4}{17}-2\frac{5}{9}+3\frac{4}{17}=\left(8+3\right)\frac{4}{17}-2\frac{5}{9}=11\frac{4}{17}-2\frac{5}{9}\)
\(\begin{array}{l}\left( {\frac{5}{{ - 4}} + 3\frac{1}{3}} \right):\frac{{10}}{9}\\ = \left( {\frac{{ - 5}}{4} + \frac{{10}}{3}} \right):\frac{{10}}{9}\\ = \left( {\frac{{ - 5.3}}{{4.3}} + \frac{{10.4}}{{3.4}}} \right):\frac{{10}}{9}\\ = \left( {\frac{{ - 15}}{{12}} + \frac{{40}}{{12}}} \right):\frac{{10}}{9}\\ = \frac{{25}}{{12}}.\frac{9}{{10}}\\ = \frac{{15}}{8}\end{array}\)\(\).
\(P=\left(-0,5-\frac{3}{5}\right):\left(-3\right)+\frac{1}{3}-\left(-\frac{1}{6}\right):\left(-2\right)\)
\(P=\left(-1,1\right):\left(-3\right)+\frac{1}{3}+\frac{1}{6}:\left(-2\right)\)
\(P=\frac{11}{30}+\frac{1}{3}+\left(-\frac{1}{12}\right)\)
\(P=\frac{37}{60}\)
\(Q=\left(\frac{2}{25}-1,008\right):\frac{4}{7}:\left[\left(3\frac{1}{4}-6\frac{5}{9}\right).2\frac{2}{17}\right]\)
\(Q=\left(-0,928\right):\frac{4}{7}:\left[\left(-\frac{119}{36}\right).2\frac{2}{17}\right]\)
\(Q=\left(-1,624\right):\left(-\frac{245}{36}\right)\)
\(Q=\frac{1044}{4375}\)
\(\frac{6}{5}\)x 5 - \(\frac{17}{5}\)= \(\frac{30}{5}\)- \(\frac{17}{5}\)=\(\frac{13}{5}\)
ta có:4/5*5+4\10*5)-17/5
=20/5+20/10)-17/5
=50/10-17/5
=10/1+(-17)/5
=-33/5
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