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a)
( x - 35 ) - 112 = 0
=> x - 35 = 0 + 112 = 112
=> x = 112 + 35 = 147
b)
124 + ( 118 - x ) = 27
=> 124 + 118 - x = 27
=> 242 - x = 27
=> x = 242 - 27 = 215
c)
156 - ( x + 61 ) = 82
=> 156 - x - 61 = 82
=> 95 - x = 82
=> x = 95 - 82 = 13
a, (X-35)-120=0
X-35 =120+0
X-35 =120
X =120+35
X =155
b,124+(118-X)=217
118-X =217-124
118-X=93
X=118-93
X=25
c,156-(X+61)=82
X+61=156-82
X+61=74
X =74-61
X =13
k cho mình đi rồi mình k lại cho
a,(x-35)-120=0
x-35=120
x=120+35
x=155
b,124+(118-x)
118-x=217-124
118-x=93
x=118-93
x=25
c,156-(x+61)=82
x+61=156-82
x+61=74
x=74-61
x=13
( x - 1 ) + 5 = 17
x - 1 = 17 - 5
x - 1 = 12
x = 12 + 1
x = 13
\(\dfrac{x-25-124}{2015}\) + \(\dfrac{x-124-2015}{25}\) + \(\dfrac{x-2015-25}{124}\) = 3
\(\dfrac{x-15-124}{2015}\) - 1 + \(\dfrac{x-124-2015}{25}\) - 1 + \(\dfrac{x-2015-25}{124}\) - 1 = 0
\(\dfrac{x-15-124-2015}{2015}\)+\(\dfrac{x-124-2015-25}{25}\)+\(\dfrac{x-2015-25-124}{124}\) = 0
\(\dfrac{x-\left(15+124+2015\right)}{2015}\)+\(\dfrac{x-\left(124+2015+25\right)}{25}\)+\(\dfrac{x-\left(2015+25+124\right)}{124}\) = 0
(\(x\) - 2164).(\(\dfrac{1}{2015}\)+\(\dfrac{1}{25}\)+\(\dfrac{1}{124}\)) = 0
\(x-2164\) = 0
\(x\) = 2164
124 x 52 - 124 x 42
=124x(52-42)
=124x10
=1240
(x+35)+(x+124)=549
=>x+35+x+124=549
=>(x+x)+(35+124)=549
=>2x+159=549
=>2x=390
=>x=195