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y =2(\(\frac{37\cdot10101}{120\cdot10101}\)-\(\frac{37\cdot10101}{6\cdot10101}\)):\(\frac{1}{x}\)=-37
y=2(37/120-37/6):1/x=-37
y=2(37/120-740/120):1/x=-37
y=2.(-703/120):1/x=-37
y=--703/60:1/x=-37
1/x=-703/60:-37
1/x=19/60
x=60/19
A=\(\frac{63x101x37-37x101x63}{1+2+3+..+2014}\)(vì 636363=63x10101 và 373737=37x101x63)
A\(\frac{0}{1+2+3+4...+2014}\)
A=0
\(A=\frac{636363\times37-373737\times63}{1+2+3+....+2014}\)
\(A=\frac{63\times10101\times37-373737\times63}{1+2+3+......+2014}\)
\(A=\frac{373737\times63-373737\times63}{1+2+3+.....+2014}\)
\(A=\frac{0}{1+2+3+.....+2014}\)
\(A=0\)
HOK TOT
Mình nghĩ đề thế này mới tính hợp lí được
2 ) B = \(1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)
B = 47/41 . ( 12/3 : 4/5 ) . 123/235
B = 47/41 . ( 4 : 4/5 ) . 123/235
B = 47/41 . 5 . 123/235
B = \(\frac{47.5.123}{41.235}\)
B = 3
1 ) A = \(\frac{636363.37-373737.63}{1+2+3+...+2006}\)
A = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)
A = \(\frac{0}{1+2+3+...+2006}\)
A = 0
Trả lời :
\(\frac{2525}{5353}\)= \(\frac{25.101}{53.101}\)= \(\frac{25}{53}\)
\(\frac{373737}{414141}\)= \(\frac{37.10101}{41.10101}\)= \(\frac{37}{41}\)
\(\frac{2525}{5353}=\frac{25.101}{53.101}=\frac{25}{53}\)( gạch 101 nhé )
\(\frac{373737}{414141}=\frac{37.10101}{41.10101}=\frac{37}{41}\)( tương tự )
hc tốt
\(27\cdot\left(\dfrac{373737}{424242}+\dfrac{373737}{565656}+\dfrac{373737}{727272}\right)\\ =27\cdot\left(\dfrac{37}{42}+\dfrac{37}{56}+\dfrac{37}{72}\right)\\ =27\cdot37\cdot\left(\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\right)\\ =999\cdot\left(\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}+\dfrac{1}{8\cdot9}\right)\\ =999\cdot\left(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}\right)\\ =999\cdot\left(\dfrac{1}{6}-\dfrac{1}{9}\right)\\ =999\cdot\dfrac{1}{18}\\ =\dfrac{111}{2}\)
Bài 2
a. \(-1\frac{2}{3}-|2x-1|:\frac{3}{5}=-2\)
\(|2x-1|:\frac{3}{5}=\frac{5}{3}-2\)
\(|2x-1|:\frac{3}{5}=-\frac{1}{3}\)
\(|2x-1|=-\frac{1}{5}\)
Vì giá trị tuyệt đối luôn \(\ge0\)với mọi x
mà \(-\frac{1}{5}< 0\)
=> \(x\in\varnothing\)
\(x=-37\)