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a)483*8+483+483
=483*8+483*1+483*1
=483*(8+1+1)
=483*10
=4830
b)620*43+620*56+620
=620*43+620*56+620*1
=620*(43+56+1)
=620*100
=62000
\(\Leftrightarrow\)\(\left(\frac{2}{3}+\frac{x}{5}\right)\)\(\times30-26=54\)
\(\Leftrightarrow20+6x\)\(-26=54\)
\(\Leftrightarrow6x=54+26-20\)
\(\Leftrightarrow6x=60\)
\(\Leftrightarrow x=10\)
Học tốt!
\(\left(\frac{4}{5}:\frac{6}{5}+\frac{1}{5}:\frac{1}{x}\right)\cdot30-26=54\)
\(\left(\frac{4}{5}\cdot\frac{5}{6}+\frac{1}{5}\cdot x\right)\cdot30=54+26\)
\(\left(\frac{2}{3}+\frac{x}{5}\right)\cdot30=80\)
\(\frac{2}{3}+\frac{x}{5}=80:30\)
\(\frac{2}{3}+\frac{x}{5}=\frac{8}{3}\)
\(\frac{x}{5}=\frac{8}{3}-\frac{2}{3}\)
\(\frac{x}{5}=2\)
\(x=10\)
\(\frac{48}{54}-x=\frac{7}{8}\Rightarrow\frac{8}{9}-x=\frac{7}{8}\)
\(\Rightarrow x=\frac{8}{9}-\frac{7}{8}=\frac{8\cdot8-9\cdot7}{72}=\frac{1}{72}\)
Vậy \(x=\frac{1}{72}\)
\(\frac{55}{60}-x=\frac{30}{45}\Rightarrow\frac{11}{12}-x=\frac{2}{3}\)
\(\Rightarrow\frac{11}{12}-\frac{12x}{12}=\frac{8}{12}\)
\(\Rightarrow11-12x=8\)
\(\Rightarrow12x=3\)
\(\Rightarrow4x=1\Rightarrow x=\frac{1}{4}\)
Vậy \(x=\frac{1}{4}\)
x + 30 = 54 + 620
x + 30 = 674
x = 674 - 30
x = 644
x+30=54+620
x+30=674
x=674-30
x=644