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\(\left(\dfrac{-5}{3}+0\right)+\dfrac{-1}{3}< x< \left(2+\dfrac{-2}{7}\right)+\dfrac{-5}{7}.\\ \Leftrightarrow-2< x< 1.\)
Mà x là số nguyên.
\(\Rightarrow x\in\left\{-1;0\right\}.\)
a) \(\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)\left(-5\right)=\left(-5\right)^5\)
b)\(\left(-2\right)\left(-2\right)\left(-2\right)\left(-3\right)\left(-3\right)\left(+3\right)=\left(-2\right)^3\cdot\left(-3\right)^2\cdot3=\left(-2\right)^3\cdot3^3\)
c) \(\left(-7\right)\cdot7\cdot5\cdot\left(-5\right)\left(-5\right)=\left(-7^2\right)\cdot\left(-5\right)^3\)
d) \(\left(-8\right)\left(-3\right)3\cdot125=\left(-2^3\right)\cdot\left(-3^2\right)\cdot5^3\)
e) \(27\cdot\left(-2\right)3\left(-7\right)\cdot49=3^4\cdot\left(-2\right)\cdot\left(-7^3\right)\)
a: \(\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)=\left(-5\right)^5\)
b: \(\left(-2\right)\cdot\left(-2\right)\cdot\left(-2\right)\cdot\left(-3\right)\cdot\left(-3\right)\cdot\left(+3\right)=\left(-2\right)^3\cdot3^3\)
a: \(=\dfrac{1}{2}\cdot\dfrac{2\cdot21+3\cdot27-5\cdot7}{189}\)
\(=\dfrac{1}{2}\cdot\dfrac{88}{189}=\dfrac{44}{189}\)
b: \(=\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}=\dfrac{1}{2}+\dfrac{4}{5}=\dfrac{13}{10}\)
c: \(=\dfrac{5}{21}-\dfrac{7}{14}\cdot\dfrac{36}{27}=\dfrac{5}{21}-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{5}{21}-\dfrac{2}{3}=\dfrac{5-14}{21}=\dfrac{-9}{21}=\dfrac{-3}{7}\)
\(\frac{1}{2}\cdot\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)=\frac{1}{2}\cdot\left(\frac{6}{27}-\frac{5}{27}+\frac{3}{7}\right)=\frac{1}{2}\cdot\frac{3}{7}+\frac{1}{2}\cdot\frac{1}{27}=\frac{3}{14}+\frac{1}{54}=\frac{44}{189}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)=\frac{1}{2}+\frac{3}{4}-\frac{3}{4}+\frac{4}{5}=\frac{1}{2}+\frac{4}{5}=\frac{13}{10}\)
\(\frac{1}{3}\cdot\frac{5}{7}-\frac{7}{27}\cdot\frac{36}{14}=\frac{1}{3}\cdot\frac{5}{7}-\frac{7}{27}\cdot\frac{18}{7}=\frac{1}{3}\cdot\frac{5}{7}-\frac{6}{7}=\frac{5}{21}-\frac{14}{21}=\frac{-3}{7}\)
a: \(\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)\cdot\left(-5\right)=\left(-5\right)^5\)
b: \(\left(-2\right)\cdot\left(-2\right)\cdot\left(-2\right)\cdot\left(-3\right)\cdot\left(-3\right)\cdot\left(+3\right)=\left(-2\right)^3\cdot3^3\)
a ) 6 18 = − 9 15 b ) − 15 35
c ) 5. ( − 4 ) 2. ( − 4 ) = 20 8 d ) 3. ( − 4 ) 2. ( − 4 ) = 12 8