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\(\frac{32\cdot2^4}{2^2\cdot\frac{1}{16}}\)
\(=\frac{2^5\cdot2^4}{\frac{4}{16}}\)
\(=\frac{2^9}{\frac{1}{4}}\)
\(=2^9\cdot4\)
\(=2^9\cdot2^2\)
\(=2^{11}\)
\(a,3^2\cdot\frac{1}{243}=3^2\cdot\frac{1}{3^5}=\frac{1}{3^3}=\frac{1^3}{3^3}=\left(\frac{1}{3}\right)^3\)
\(b,81^2\cdot\frac{1}{3^3}=\left(3^4\right)^2\cdot\frac{1}{3^3}=3^8\cdot\frac{1}{3^3}=3^5\)
a) \(3^2.\frac{1}{243}=\frac{1.3^3}{243}=\frac{3^2}{243}=\frac{3^2}{3^5}=\frac{1}{3^3}=\frac{1}{27}\)
b) \(81^2.\frac{1}{3^3}=\frac{1.81^2}{3^3}=\frac{81^2}{3^3}=\frac{3^8}{3^3}=3^5=243\)
\(3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)
\(=\frac{3^2}{3^3}\cdot\frac{81\cdot81}{81\cdot3}\)
\(=\frac{1}{3}\cdot\frac{27}{1}\)
\(=9=\left(\pm3\right)^2\)
a: \(2^6\cdot3^3=\left(2^2\cdot3\right)^3=12^3\)
b: \(6^4\cdot8^3=2^4\cdot3^4\cdot2^9=2^{13}\cdot3^4\)
c: \(16\cdot81=36^2\)
d: \(25^4\cdot2^8=100^4\)
=(1/2) mu 15*(1/2 mu 2) mu 20
=1/2 mu 15*1/2 mu 40
=1/2 mu 55
Dung thi k ung ho minh nha!Thanks!!!
32 . 24 : ( 22 . 1/16 )
= 25 . 24 : 1/22
= 29 . 22
= 211
\(\frac{2^7}{16}\)