Question

[Cô Bé Xinh Xắn]

Tính:

a, A= \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}+6^{11}}\)

b, B= \(\frac{1}{\frac{1-1}{1-2^{-1}}}\) + \(\frac{1}{1+\frac{1}{1+2^{-1}}}\)

Answer 1

[Đinh Phương Thảo]

\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}+6^{11}}=\frac{2^6.2^6.3^5.3^5+2^9.3^9.2.2.2.5}{2^4.2^4.2^4.3^{12}+2^{11}.3^{11}}\)\(=\frac{2^{12}.3^{10}.5}{3^2+2^{11}.3^{11}}=\frac{2.5}{3^3}=\frac{10}{27}\)