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1.Đổi 600 kg = \(\frac{3}{5}\)tấn .
Vậy chiếc xe tải nặng số kg là :
2 - \(\frac{3}{5}\)=\(\frac{7}{5}\)(tấn)
\(\dfrac{4}{5}+x=3\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{4}{5}+x=\dfrac{16}{5}\)
\(\Leftrightarrow0,8+x=3,2\)
\(\Leftrightarrow x=3,2-0,8\)
\(\Leftrightarrow x=2,4\)
\(\dfrac{4}{5}+x=3\dfrac{1}{5}\)
⇔ \(\dfrac{4}{5}+x=\dfrac{16}{5}\)
⇔ \(x=\dfrac{12}{5}=2,4\)
a;
c; \(\dfrac{1}{10}\) + \(\dfrac{4}{20}\) + \(\dfrac{9}{30}\)+\(\dfrac{16}{40}+\dfrac{25}{50}+\dfrac{36}{60}+\dfrac{49}{70}+\dfrac{64}{80}+\dfrac{81}{90}\)
= \(\dfrac{1}{10}+\dfrac{2}{10}+\dfrac{3}{10}+\dfrac{4}{10}+\dfrac{5}{10}+\dfrac{6}{10}+\dfrac{7}{10}+\dfrac{8}{10}+\dfrac{9}{10}\)
= \(\dfrac{1+2+3+4+5+6+7+8+9}{10}\)
= \(\dfrac{\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5}{10}\)
= \(\dfrac{10+10+10+10+5}{10}\)
= \(\dfrac{\left(10+10+10+10\right)+5}{10}\)
= \(\dfrac{10\times4+5}{10}\)
= \(\dfrac{45}{10}\)
= \(\dfrac{9}{2}\)
a: \(12:\dfrac{3}{4}+75\%\cdot\dfrac{1}{2}-16\cdot50\%\)
\(=12\cdot\dfrac{4}{3}+\dfrac{3}{4}\cdot\dfrac{1}{2}-16\cdot0,5\)
\(=16-8+\dfrac{3}{8}\)
\(=8,375\)
b: \(75\%\cdot4+22,5:3-1\dfrac{3}{5}\)
\(=0,75\cdot4+7,5-1,6\)
\(=3+7,5-1,6\)
=10,5-1,6
=8,9
a)A=1.1189
b)B=1/21/68