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(5 + 6 + 11 - 41) x (1 + 2 + 3 + ... + 100)
= [(5 + 6) - (11 - 41)] x (1 + 2 +...+ 100)
= [11 - 30 ] x (1 + 2 + ... + 100)
= - 19 x (1 + 2 +...+ 100)
Lớp 5 chưa học số âm.
12 x 85 + 35 - 182 - 35 x 94
= 1020 - 35 x (94 - 1) - 182
= 1020 - 35 x 93 - 182
= 1020 - 3255 - 182
= - 2235 - 182
= - 2417
Lớp 5 chưa học số âm
a, \(\dfrac{90}{37}-\dfrac{38}{25}-\dfrac{8}{25}-\dfrac{4}{25}\)
= \(\dfrac{90}{37}\) - \(\dfrac{38+8+4}{25}\)
= \(\dfrac{90}{37}\) - 2
= \(\dfrac{16}{37}\)
\(\dfrac{24}{29}\) + \(\dfrac{32}{41}\) + \(\dfrac{34}{29}\) + \(\dfrac{50}{41}\)
=(\(\dfrac{24}{29}\) + \(\dfrac{34}{29}\)) + (\(\dfrac{32}{41}\) + \(\dfrac{50}{41}\))
= \(\dfrac{58}{29}\) + \(\dfrac{82}{41}\)
= 2 + 2
= 4
A=1+1/2+1+1/6+1+1/12+...+1+1/90=
=9+1/2+1/6+1/12+...+1/90
1/2+1/6+1/12+...+1/90=
1/1x2+1/2x3+2/3x4+...+1/9x10=
\(=\dfrac{2-1}{1x2}+\dfrac{3-2}{2x3}+\dfrac{4-3}{3x4}+...+\dfrac{10-9}{9x10}=\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}=\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
\(\Rightarrow A=9+\dfrac{9}{10}=9\dfrac{9}{10}\)
\(2.31.12+4.6.42+8.27.3\)
\(=2.31.3.4+4.42.2.3+8.27.3\)
\(=248.3+336.3+216.3\)
\(=3.\left(248+336+216\right)\)
\(=3.800\)
\(=2400\)
dung day
8 x 12 x 32 + 4 x 27 x 24 + 41 x 6 x 16
=96 x 32 + 96 x 27 + 96 x 41
=96 x (32 + 27 + 41)
= 96 x 100
=9600
A = 8 × 12 × 32 + 4 × 27 × 24 + 41 × 6 × 16
A = 8 × 12 × 32 + 4 × 24 × 27 + 6 × 16 × 41
A = 96 × 32 + 96 × 27 + 96 × 41
A = 96 × (32 + 27 + 41)
A = 96 × 100
A = 9600
a)\(\frac{24}{x}\times\frac{1}{4}=\frac{2}{5}\)
\(\frac{24}{x}=\frac{2}{5}:\frac{1}{4}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(x=24:\frac{8}{5}\)
\(x=15\)