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1012
= (100 + 1)²
= 100² + 2.100.1 + 1²
= 10000 + 200 + 1
= 10201
a. 1012 = 10201
b. 97 x 103 = 9991
c. 772 + 232 + 77 x 46
= 5929 + 529 + 77 x 46
= 5929 + 529 + 3542
= 6458 + 3542
= 10000
d. 1052 - 5
= 11025 - 5
= 11020
a) 1012
= (100 + 1)2
= 1002 + 2.100 + 1
= 10000 + 200 + 1
= 10201
b) 97.103
= (100 - 3)(100 + 3)
= 1002 - 32
= 10000 - 9
= 9991
c) 772 + 232 + 77.46
= 772 + 2.77.23 + 232
= (77 + 23)2
= 1002
= 10000
d) 1052 - 52
= (105 - 5)(105 + 5)
= 100.110
= 11000
a) \(101^2=\left(100+1\right)^2=100^2+2\cdot100\cdot1+1^2=10000+200+1=10201\)
b) \(97\cdot103=\left(100-3\right)\left(100+3\right)=100^2-3^2=10000-9=9991\)
c) \(77^2+23^2+77\cdot46\)
\(=77^2+2\cdot77\cdot23+23^2\)
\(=\left(77+23\right)^2=100^2=10000\)
d) \(105^2-5^2=\left(105-5\right)\left(105+5\right)=100\cdot110=11000\)
a. \(^{77^2}\) + \(23^2\) + 77 . 46
= \(77^2\) + 2. 77 . 23 + \(23^2\)
= \(\left(77+23\right)^2\)
= \(100^2\)
= 10000
b. \(105^2\) - \(5^2\)
= ( 105 - 5)( 105 + 5)
= 100 . 110
= 11000
a) \(101^2\)
\(=\left(100+1\right)^2\)
\(=100^2+2.100.1+1^2\)
\(=10000+200+1\)
\(=10200+1\)
\(=10201\)
b) \(97.103\)
\(=\left(100-3\right).\left(100+3\right)\)
\(=100^2-3^2\)
\(=10000-9\)
\(=9991\)
c) \(77^2+23^2+77.46\)
\(=77^2+77.46+23^2\)
\(=77^2+2.77.23+23^2\)
\(=\left(77+23\right)^2\)
\(=100^2\)
\(=10000\)
d) \(105^2-5^2\)
\(=\left(105-5\right)\left(105+5\right)\)
\(=100.110\)
\(=11000\)
lâu lắm r moi lên h24, tớ giúp bn nhé:
*1012 = (100+1)2 = 104 + 2.100.1 +12 = 10201
*97.103= (100-3)(100+3) = 102 - 32 = 9991
* = 772 + 2.77.23 + 232 = (77+23)2 = 104
a.\(^{101^2}\)= 10201
b.97 x 103 = 9991
c.\(^{77^2}+^{23^2}+77\times46\)=10000
d.\(^{105^5}-^{5^2}\)= 12762815600
a) 1012 = (100 - 1)2 = 1002 - 200 + 1 = 10000 - 200 + 1 = 9801
b) 97 x 103 = (100 - 3)(100 + 3) = 1002 - 32 = 10000 - 9 = 9991
c) 772 + 232 + 77*46 = (77 + 23)2 = 1002 = 10000
d) 1052 - 52 = (105 + 5)(105 - 5) = 110 * 100 = 11000