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\(A=\frac{\left(23\frac{11}{15}-26\frac{13}{20}\right)}{12^2+5^2}\cdot\frac{1-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}}{3^2.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+\frac{11}{15}-26+\frac{13}{20}\right)}{144+25}\cdot\frac{1-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}}{9.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+26+\frac{11}{15}-\frac{13}{20}\right)}{169}\cdot\frac{1-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)}{13.\left(9.2-5\right)}-\frac{19}{37}\)
\(A=\frac{49+\frac{44}{60}-\frac{39}{60}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}}{13.13}-\frac{19}{37}\)
\(A=\frac{49+\frac{1}{20}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{8}}{169}-\frac{19}{37}\)
\(A=\frac{49\frac{1}{20}}{169}\cdot\frac{\frac{4}{5}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{32}{40}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{37}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981.\frac{37}{40}}{169^2}-\frac{19}{37}\)
\(A=\frac{\frac{36297}{40}}{28561}-\frac{19}{37}\)
\(A=\frac{907,425}{28561}-\frac{19}{37}\)
\(A=\frac{33574,725}{1056757}-\frac{542659}{1056757}\)
\(A=\frac{-509084,275}{1056757}=-0,04604282...\)
Mik chỉ làm đc thế này thôi, ôn thi học kì II tốt nha bạn!
Ta có : \(S=1.4+4.7+7.10+.......+91.94\)
=> \(6S=1.4.7-1.4.7+7.10.13-7.10.13+.......+91.94.97\)
=> \(6S=91.94.97\)
=> \(6S=829738\)
=> \(S=\frac{829738}{6}\)
\(\frac{1}{12}+\frac{1}{20}+\frac{1}{42}+.....+\frac{1}{132}\)
\(=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{11.12}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+......+\frac{1}{11}-\frac{1}{12}\)
\(=\frac{1}{3}-\frac{1}{12}\)
\(=\frac{1}{4}\)
\(a,S=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{19}+3^{20}\right)\\ S=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{18}\left(3+3^2\right)\\ S=\left(3+3^2\right)\left(1+3^2+...+3^{18}\right)=12\left(1+3^2+...+3^{18}\right)⋮12\)
\(b,S=\left(3+3^2+3^3+3^4\right)+...+\left(3^{17}+3^{18}+3^{19}+3^{20}\right)\\ S=\left(3+3^2+3^3+3^4\right)+....+3^{16}\left(3+3^2+3^3+3^4\right)\\ S=\left(3+3^2+3^3+3^4\right)\left(1+...+3^{16}\right)\\ S=120\left(1+...+3^{16}\right)⋮120\)
\(a,S=3+3^2+3^3+...+3^{20}\)
Ta thấy:\(3+3^2=12⋮12\)
\(\Rightarrow S=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{18}\left(3+3^2\right)\\ \Rightarrow S=\left(3+3^2\right)\left(1+3^2+...+1^{18}\right)\\ \Rightarrow S=12.\left(1+3^2+...+3^{18}\right)⋮12\\ \left(đpcm\right)\)
\(b,Ta\) \(thấy:\)\(3+3^2+3^3+3^4=120⋮120\)
\(\Rightarrow S=\left(3+3^2+3^3+3^4\right)+...+\left(3^{17}+3^{18}+3^{19}+3^{20}\right)\\ \Rightarrow S=\left(3+3^2+3^3+3^4\right)+...+3^{16}\left(3+3^2+3^3+3^4\right)\\ \Rightarrow S=\left(3+3^2+3^3+3^4\right)\left(1+...+3^{16}\right)\\ \Rightarrow S=120\left(1+...+3^{16}\right)⋮120\\ \left(đpcm\right)\)
-1 +2 - 3 + 4 - 5 + 6 + ........ + 2010 - 2011
= -1 + -1 + -1 + -1 + ......... + - 1
= [ ( - 1 ) - ( -1 ) ] + 1
= 0+1
=1
Chúc bạn học tốt nha
\(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+....+\frac{3}{40\cdot43}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+....+\frac{1}{40}-\frac{1}{43}\)
\(=1-\frac{1}{43}=\frac{42}{43}\)
Đặt A = 1 + ( - 2 ) + 3 + ( - 4 ) + ..... + 19 + ( - 20 )
=) Số Số Hạng của A là : ( 20 - 1 ) : 1 + 1 = 20
=) Số Cặp của A là : 20 : 2 = 10
=) A = ( -1 ) + ( -1 ) + ( -1 ) +.......+ ( -1 )
=) A = ( -1 ) . 20 = -20
= [1+(-2)] + [3+(-4)] + [5+ ( -6)] + ... + [19 + ( -20]
= (-1) + (-1) + ... + ( -1) có 20 số -1
= -1. 20
= -20
Tính bằng cách nhanh nhất :
Câu 1 : 47 nhân 54 + 49 nhân 46
=(46+54)x(47x49)
=230300
S=1/20+1/44+1/77+...+1/3080
S=1/20+1/44+1/77+...+1/3080
S.3/2=3/40+3/88+3/154+...+3/6160
S.3/2=3/40+3/88+3/154+...+3/6160
S.3/2=3/5.8+3/8.11+3/11.14+...+3/77.80
S.3/2=3/5.8+3/8.11+3/11.14+...+3/77.80
S.3/2=1/5−1/8+1/8−1/11+1/11−1/14+...+1/77−1/80
S.3/2=1/5-1/8+1/8-1/11+1/11-1/14+...+1/77-1/80
S.3/2=1/5−1/80
S.3/2=1/5-1/80
S.3/2=3/16
S.3/2=3/16
S=3/16:3/2
S=3/16:3/2
S=1/8
sai chỗ nào bạn thông cảm cho