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`2.24.25 + 3.41.16 + 6.2.8.17`
`= 48*25 + 48*41 + 48*2*17`
`= 48*(25+41+2*17)`
`= 48*(66+34)`
`= 48*100 `
`= 4800`
2.24.25 + 3.41.16 + 6.2.8.17
= ( 2.24 ).25 + ( 3.16 ).41 + ( 6.8 ) + ( 2.17 )
= 48 . 25 + 48 .41 + 48 . 34
= 48. ( 25 + 41 + 34 )
= 48 . 100
= 4800
3.18.25 + 3.41.16 + 6.2.8.17
= 3.18.25 + 3.16.41 + (6.8).(2.17)
= 48.25 + 48.41 + 48.34
= 48.(25 + 41 + 34)
= 48.100
= 4800
\(2.24.25+3.31.16+6.2.8.17\)
\(=48.25+48.31+48.34\)
\(=48.\left(25+31+24\right)\)
\(=48.90\)
\(=4320\)
a) 86 + 357 + 14 = (86 + 14) + 357
= 100 + 357
= 457
b) 25 . 13 . 4 = (25 . 4) . 13
= 100 . 13
= 1300
c) 28 . 64 + 28 . 36 = 28 . (64 + 36)
= 28 . 100
=2800
a) 86 + 357 + 14
= ( 86 + 14 ) + 357
= 100 + 537
= 637
b)25 . 13 . 4
= ( 25 . 4 ) . 13
= 100 . 13
= 1300
c) 28 . ( 64 + 36 )
= 28 . 100
= 2800
=(-259+259)+[(-74)+(-26)]+(-81+581)
=0+(-100)+500
=400
= -259 + 259 - 74 - 26 + 581 + 259 - 81
= 0 - 100 + 840 - 81
= 659
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{8}{9}-\frac{51}{13}.\frac{1}{3}\)
\(=\frac{7}{5}-\left(\frac{32}{60}+\frac{15}{60}\right).\frac{8}{9}-\frac{17}{13}\)
\(=\frac{7}{5}-\frac{47}{60}.\frac{8}{9}-\frac{17}{13}\)
\(=\frac{7}{5}-\frac{94}{135}-\frac{17}{13}\)
\(=\frac{-212}{351}\)
Tự quy đồng
\(2\frac{3}{4}.\left(-0,4\right)-1\frac{3}{5}.2,75+\left(-1,2\right):\frac{4}{11}\)
\(=\frac{11}{4}.\frac{-2}{5}-\frac{8}{5}.\frac{11}{4}-\frac{6}{5}.\frac{11}{4}\)
\(=\frac{11}{4}.\left(\frac{-2}{5}-\frac{8}{5}-\frac{6}{5}\right)\)
\(=\frac{11}{4}.\frac{-16}{5}\)
\(=\frac{-44}{5}=-8\frac{4}{5}\)
\(=2.6\cdot\left(-2\right):2=2.6\cdot\left(-1\right)=-2.6\)
25 . 13 . 4 + 2 . 17 . 50
= 25 . 13 + 2 . 17 . 25 . 2
= 25 . 13 +
=100.13+100.17=(13+17).100=30.100=3000
b)=2.48+48.41+48.34
=48.(2+41+34)
=48.77
=3696