Question

[Đinh Ngọc Mai]

Tính giá trị biểu thức:

A=(4^5×9^4+2×6^9):(2^10×3^8-6^8×2)

Answer 1

[tttttt126]

đáp án 194

Answer 2

[Kiệt Nguyễn]

\(A=\left(4^5\times9^4+2\times6^9\right)\div\left(2^{10}\times3^8-6^8\times2\right)\)

\(\Leftrightarrow A=\frac{4^5\times9^4+2\times6^9}{2^{10}\times3^8-6^8\times2}\)

\(\Leftrightarrow A=\frac{\left(2^2\right)^5\times\left(3^2\right)^4+2\times\left(3\times2\right)^9}{2^{10}\times3^8-\left(3\times2\right)^8\times2}\)

\(\Leftrightarrow A=\frac{2^{10}\times3^8+2\times3^9\times2^9}{2^{10}\times3^8-3^8\times2^8\times2}\)

\(\Leftrightarrow A=\frac{2^{10}\times3^8+2^{10}\times3^8\times3}{2^{10}\times3^8-3^8\times2^9}\)

\(\Leftrightarrow A=\frac{3^8\left(2^{10}+2^{10}\times3\right)}{3^8\left(2^{10}-2^9\right)}\)

\(\Leftrightarrow A=\frac{2^{10}+2^{10}\times3}{2^{10}-2^9}\)

\(\Leftrightarrow A=\frac{2^{10}\left(1+3\right)}{2^9\left(2-1\right)}\)

\(\Leftrightarrow A=\frac{2\left(1+3\right)}{2-1}\)

\(\Leftrightarrow A=\frac{2\times4}{1}\)

\(\Leftrightarrow A=8\)