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a: \(232-\left(581+132-331\right)\)
\(=232-581-132+331\)
\(=\left(232-132\right)+\left(-581+331\right)\)
\(=100-250\)
=-150
b: \(\left[12+\left(-57\right)\right]-\left[-57-\left(-12\right)\right]\)
\(=12+\left(-57\right)+57+\left(-12\right)\)
\(=\left(12-12\right)+\left(57-57\right)\)
=0+0
=0
a) \(A=27\cdot36+73\cdot99+27\cdot14-49\cdot73\)
\(A=27\cdot\left(36+14\right)+73\cdot\left(99-49\right)\)
\(A=27\cdot50+73\cdot50\)
\(A=50\cdot\left(27+73\right)\)
\(A=50\cdot100\)
\(A=5000\)
b) \(B=\left(4^5\cdot10\cdot5^6+25^5\cdot2^8\right):\left(2^8\cdot5^4+5^7\cdot2^5\right)\)
\(B=\dfrac{\left(2^2\right)^5\cdot2\cdot5\cdot5^6+\left(5^2\right)^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B=\dfrac{2^{11}\cdot5^7+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(B-\dfrac{2^8\cdot5^7\cdot\left(2^3\cdot1+5^3\cdot1\right)}{2^5\cdot5^4\cdot\left(2^3\cdot1+5^3\cdot1\right)}\)
\(B=\dfrac{2^8\cdot5^7}{2^5\cdot5^4}\)
\(B=2^3\cdot5^3\)
\(B=10^3\)
\(B=1000\)
a: \(A=\dfrac{5}{7}-\dfrac{2}{7}+\dfrac{8}{11}+\dfrac{3}{11}+\dfrac{1}{2}=\dfrac{3}{7}+\dfrac{1}{2}+1=\dfrac{6+7+14}{14}=\dfrac{27}{14}\)
b: \(B=\dfrac{11}{17}+\dfrac{6}{17}-\dfrac{8}{19}-\dfrac{30}{19}+\dfrac{-3}{4}=1-2-\dfrac{3}{4}=-1-\dfrac{3}{4}=-\dfrac{7}{4}\)
c: \(C=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}=\dfrac{49}{50}\)
a: =382-282+531-331
=100+200=300
b: =(7-8)+(9-10)+...+(2009-2010)
=(-1)+(-1)+....+(-1)
=-1002
c: =-(1+2+3+...+2009+2010)
=-2010*2011/2=-2021055
a) 4,38 - 1,9 + 0,62 b) [(-100).(-1,6)]:(-2)
= (4,38 + 0,62) - 1,9 = 100.1,6 : (-2)
= 5 - 1,9 = 3,1 = 160 : (-2) = -80
c) (2,4.5,55): 1,11 d) 100. (2,01 + 3,99)
= 2,4. (5,55:1,11) = 100. 6
= 2,4. 5 =12 = 600
a: =-1,93+0,895=-1,035
b: =-1,6+0,93-0,131=-1,6+0,799=-0,801
c: =-3.87+9,07-2,8=5,2-2,8=2,4