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20 tháng 3 2020

A = 1/3 -3/4--3/5+1/73-1/26+1/15-2/9

A = (1/3+3/5+1/15)-3/4+1/73-1/26-2/9

A = 15/15 - 472/468 +1/73

A = 1 - 34924/34164

A = -760/34164

A = -190/8541

22 tháng 3 2020

\(A=\frac{1}{3}-\frac{3}{4}-\frac{-3}{5}+\frac{1}{73}-\frac{1}{26}+\frac{1}{15}+\frac{-2}{9}\)

\(\Rightarrow A=\left(\frac{1}{3}-\frac{-3}{5}+\frac{1}{15}\right)-\frac{3}{4}+\frac{1}{73}-\frac{1}{26}+\frac{-2}{9}\)

\(\Rightarrow A=\left(\frac{5}{15}-\frac{-9}{15}+\frac{1}{15}\right)-\frac{39}{52}-\frac{2}{52}+\frac{1}{73}+\frac{-2}{9}\)

\(\Rightarrow A=\left(\frac{5}{15}+\frac{9}{15}+\frac{1}{15}\right)-\left(\frac{39}{52}+\frac{2}{52}\right)+\frac{9}{657}+\frac{-146}{657}\)

\(\Rightarrow A=1-\frac{41}{52}+\frac{-137}{657}=\frac{11}{52}+\frac{-137}{657}=\frac{7227}{34164}+\frac{-7124}{34164}=\frac{103}{34163}\)

Vậy \(A=\frac{103}{34164}\)

Chúc bn học tốt

11 tháng 6

a; \(\dfrac{3}{11}\) + \(\dfrac{5}{-9}\) + \(\dfrac{4}{11}\) - \(\dfrac{4}{9}\) + \(\dfrac{3}{17}\) + \(\dfrac{15}{11}\)

= (\(\dfrac{3}{11}\) + \(\dfrac{4}{11}\) + \(\dfrac{15}{11}\)) - (\(\dfrac{5}{9}\) + \(\dfrac{4}{9}\)) + \(\dfrac{3}{17}\)

= 2 - 1 + \(\dfrac{3}{17}\)

= 1 + \(\dfrac{3}{17}\)

\(\dfrac{20}{17}\) 

11 tháng 6

c; N = \(\dfrac{\dfrac{5}{7}-\dfrac{5}{9}-\dfrac{5}{11}}{\dfrac{15}{7}+\dfrac{15}{9}+\dfrac{15}{11}}\)

   Phải là - \(\dfrac{5}{7}\) chỗ tử số mới đúng em nhé!

Ta có: \(A=\frac{1}{3}-\frac{3}{4}+\frac{3}{5}+\frac{1}{73}-\frac{1}{36}+\frac{1}{15}-\frac{2}{9}\)

\(A=\left(\frac{1}{3}-\frac{2}{9}\right)+\left(\frac{3}{5}+\frac{1}{15}\right)-\frac{3}{4}-\frac{1}{36}+\frac{1}{73}\)

\(A=\left(\frac{3}{9}-\frac{2}{9}\right)+\left(\frac{9}{15}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{1}{36}\right)+\frac{1}{73}\)

\(A=\frac{1}{9}+\frac{10}{15}-\frac{7}{9}+\frac{1}{73}\)

\(A=\frac{1}{9}+\frac{2}{3}-\frac{7}{9}+\frac{1}{73}\)

\(A=\frac{1}{9}+\frac{6}{9}-\frac{7}{9}+\frac{1}{73}\)

\(A=\frac{7}{9}-\frac{7}{9}+\frac{1}{73}\)

\(A=\frac{1}{73}\)

Vậy: \(A=\frac{1}{73}\)

29 tháng 4 2019

cho mik hỏi k kiểu j z

7 tháng 6 2020

\(1)\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{1}{3}\)

\(=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}\right)\)

\(=\frac{1}{3}.2\)

\(=\frac{2}{3}\)

7 tháng 6 2020

\(1)\)\(\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{1}{3}\)

\(=\frac{1}{3}.\left(\frac{4}{5}+\frac{6}{5}-1\right)\)

\(=\frac{1}{3}.\left(\frac{4}{5}+\frac{6}{5}-\frac{5}{5}\right)\)

\(=\frac{1}{3}.1\)

\(=\frac{1}{3}\)

\(2)\)\(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}\)

\(=\frac{1}{7}.\frac{27}{26}-\frac{1}{7}.\frac{1}{26}\)

\(=\left(\frac{27}{26}-\frac{1}{26}\right).\frac{1}{7}\)

\(=1.\frac{1}{7}\)

\(=\frac{1}{7}\)

\(3)\)\(15\left(\frac{1}{5}-\frac{7}{15}+\frac{17}{3}\right)\)

\(=3-7+85\)

\(=81\)

\(4)\)\(38\left(2\frac{1}{19}-5\frac{7}{38}\right)\)

\(=38\left(\frac{39}{19}-\frac{197}{38}\right)\)

\(=78-197\)

\(=-119\)

\(5)\)\(75\left(\frac{-4}{25}+7\frac{1}{15}-5\frac{7}{75}\right)\)

\(=75\left(\frac{-4}{25}+\frac{106}{15}-\frac{382}{75}\right)\)

\(=-12+530-382\)

\(=136\)

Ddaeng

25 tháng 8 2018

\(a,\frac{47}{9}+\left(\frac{41}{3}-\frac{26}{9}\right)\)

\(=\frac{47}{9}+\left(\frac{82}{9}-\frac{26}{9}\right)\)

\(=\frac{47}{9}+\frac{56}{9}\)

\(=\frac{103}{9}\)

\(b,\frac{26}{15}:\frac{13}{5}-\frac{1}{4}\)

\(=\frac{26.5}{15.3}-\frac{1}{4}\)

\(=\frac{12}{3}-\frac{1}{4}\)

\(=\frac{4}{1}-\frac{1}{4}=\frac{16}{4}-\frac{1}{4}=\frac{15}{4}\)

19 tháng 7 2016

a) \(\frac{15}{16}\cdot\frac{4}{3}-\frac{1}{2}:\frac{5}{4}+3\)

\(=\frac{5}{4}-\frac{2}{5}+3\)

\(=\frac{25}{20}-\frac{8}{20}+\frac{60}{20}\)

\(=\frac{77}{20}=3\frac{17}{20}\)

b) \(\left(\frac{2}{3}-\frac{3}{8}\right):\left(\frac{3}{5}+\frac{1}{4}\right)\)

\(=\frac{7}{24}:\frac{17}{20}\)

\(=\frac{35}{102}\)

c) \(\frac{15}{8}\cdot\left(\frac{1}{3}+\frac{1}{8}\right)-\frac{3}{8}:\frac{3}{4}\)

\(=\frac{15}{8}\cdot\frac{11}{24}-\frac{1}{2}\)

\(=\frac{55}{64}-\frac{1}{2}\)

\(=\frac{23}{64}\)

d) \(\frac{20}{21}:\left(\frac{4}{5}-\frac{1}{10}\right)+\frac{13}{15}:\frac{5}{26}\)

\(=\frac{20}{21}:\frac{7}{10}+\frac{52}{15}\)

\(=\frac{200}{147}+\frac{52}{15}\)

\(=4\frac{608}{735}\)