Câu hỏi của Vũ Hồng Ngọc

Question

tính : 8^2 x 125 x 9^2 - 32 x 5^3 x 81 phần 20^3 x 3^4 - 6^8 x 5^4

Nguyễn Đức Trí · Accepted Answer

$\dfrac{8^2.125.9^2-32.5^3.81}{20^3.3^4-6^8.5^4}$

$=\dfrac{2^6.5^3.3^4-2^5.5^3.3^4}{4^3.5^3.3^4-2^8.3^8.5^4}$

$=\dfrac{2^6.5^3.3^4-2^5.5^3.3^4}{2^6.5^3.3^4-2^8.3^8.5^4}$

$=\dfrac{2^5.5^3.3^4\left(2-1\right)}{2^6.5^3.3^4\left(1-2^2.3^4.5\right)}$

$=\dfrac{2^5.5^3.3^4.1}{2^6.5^3.3^4\left(1-810\right)}$

$=\dfrac{1}{2.\left(-809\right)}$

$=-\dfrac{1}{1618}$Câu trả lời: $\dfrac{8^2.125.9^2-32.5^3.81}{20^3.3^4-6^8.5^4}$

$=\dfrac{2^6.5^3.3^4-2^5.5^3.3^4}{4^3.5^3.3^4-2^8.3^8.5^4}$

$=\dfrac{2^6.5^3.3^4-2^5.5^3.3^4}{2^6.5^3.3^4-2^8.3^8.5^4}$

$=\dfrac{2^5.5^3.3^4\left(2-1\right)}{2^6.5^3.3^4\left(1-2^2.3^4.5\right)}$

$=\dfrac{2^5.5^3.3^4.1}{2^6.5^3.3^4\left(1-810\right)}$

$=\dfrac{1}{2.\left(-809\right)}$

$=-\dfrac{1}{1618}$