Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(9x7x\frac{y}{42}x63=\frac{5}{6}\)
\(3969x\frac{y}{42}=\frac{5}{6}\)
\(\frac{166698}{42}x\frac{y}{42}=\frac{35}{42}\)
\(166698\)x y=35
\(y=166698:35\)
y=4762,8
a) \(\frac{7}{10}-y\cdot\frac{3}{4}=\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{1}{2}\)
\(y=\frac{1}{2}:\frac{3}{4}\)
\(y=\frac{1}{2}\cdot\frac{4}{3}\)
\(y=\frac{2}{3}\)
b) \(\frac{5}{6}:\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}:\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}\cdot\frac{4}{3}\)
\(y+\frac{7}{9}=\frac{10}{9}\)
\(y=\frac{10}{9}-\frac{7}{9}\)
\(y=\frac{3}{9}=\frac{1}{3}\)
**** !
a, \(\frac{7}{10}-y\times\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow y=\frac{1}{2}\div\frac{3}{4}\)
\(\Rightarrow y=\frac{1}{3}\)
b, \(\frac{5}{6}\div\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{5}{6}\div\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{10}{9}\)
\(\Rightarrow y=\frac{10}{9}-\frac{7}{9}\)
\(\Rightarrow y=\frac{1}{3}\)
a) 7/10 - y × 3/4 = 1/5
y × 3/4 = 7/10 - 1/5
y × 3/4 = 1/2
y = 1/2 : 3/4
y = 2/3. Vậy y = 2/3
b) 5/6 : ( y + 7/9 ) = 3/4
y + 7/9 = 5/6 : 3/4
y + 7/9 = 10/9
y. = 10/9 - 7/9
y = 1/3. Vậy y = 1/3
\(\frac{7}{10}\)- y * \(\frac{3}{4}\)= \(\frac{1}{5}\)
y * \(\frac{3}{4}\)= \(\frac{7}{10}\)- \(\frac{1}{5}\)
y * \(\frac{3}{4}\)= \(\frac{1}{2}\)
y = \(\frac{1}{2}\): \(\frac{3}{4}\)
y = \(\frac{2}{3}\)
Vậy y = \(\frac{2}{3}\)
\(\frac{5}{6}\): ( y + \(\frac{7}{9}\)) = \(\frac{3}{4}\)
y + \(\frac{7}{9}\) = \(\frac{5}{6}\): \(\frac{3}{4}\)
y + \(\frac{7}{9}\) = \(\frac{10}{9}\)
y = \(\frac{10}{9}\)- \(\frac{7}{9}\)
y = \(\frac{3}{9}\)
Vậy y = \(\frac{3}{9}\)
a. =(1+10)×10 :2
=11×10:2
=110:2
=55
b. Số các số hạng là =(90-9):9+1= 10
Tổng = (9+90)×10:2=495
y =10 tk và kết bạn với mình nha
nếu ai tk cho mình thì người đó thi sẽ được điểm cao
y x 5 + y x 6 - y x 1- 37=63
y x 5 + y x 6 - y x 1=63+37
y x (5+6-1)=100
y x 10=100
y=100:10
y=10
y x 5 + y x 6 - y - 37 = 63
y x 5 + y x 6 - y = 63 + 37
y x 5 + y x 6 - y = 100
y x (5 + 6 - 1) = 100
y x 10 = 100
y = 100 : 10
y = 10
y x 5 + y x 6 - y - 37 = 63
y x 5 + y x 6 - y x 1 - 37 = 63
y x ( 5 + 6 - 1 ) - 37 = 63
y x 10 - 37 = 63
y x 10 = 63 + 37
y x 10 = 100
y = 100 : 10
y = 10
\(\frac{2}{3}:\frac{y}{9}:\frac{7}{5}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\)
\(\frac{2}{3}\cdot\frac{9}{y}\cdot\frac{5}{7}=\frac{2}{7}\cdot\frac{5}{3}\cdot\frac{9}{10}\)
\(\frac{2\cdot9\cdot5}{3\cdot y\cdot7}=\frac{2\cdot5\cdot9}{7\cdot3\cdot10}\)
\(\frac{30}{7\cdot y}=\frac{3}{7}\)
\(\Leftrightarrow30\cdot7=7\cdot y\cdot3\)
210 = 21 * y
y = 10
2/3 : y/9 : 7/5 = 2/7 : 3/5 : 10/9
= 2/3 : y/9 : 7/5 = 3/70
= 2/3 : y/9 = 3/70 x 7/5
= 2/3 : y/9 = 3/50
y/9 = 2/3 : 3/50
y/9 = 100/9
vậy y = 100
\(\frac{9\cdot7\cdot y}{72\cdot63}=\frac{5}{6}\)
Ta có : \(\frac{9\cdot7\cdot y}{9\cdot8\cdot7\cdot9}=\frac{5}{6}\)
\(\Rightarrow\frac{1\cdot y}{8\cdot9}=\frac{5}{6}\)
\(\Rightarrow\frac{1\cdot y}{72}=\frac{5}{6}\Rightarrow y=60\)
Do đó , y = 60