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DT
1
14 tháng 4 2019
\(\frac{4}{15}:y=\left(\frac{4}{5}+\frac{1}{2}\right)\times\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{13}{10}\times\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{2}{5}\)
\(y=\frac{4}{15}:\frac{2}{5}\)
\(y=\frac{2}{3}\)
HV
3
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
15 tháng 4 2023
y \(\times\) \(\dfrac{16}{64}\) + y \(\times\) \(\dfrac{25}{100}\) + y \(\times\) \(\dfrac{1}{4}\) + y \(\times\) \(\dfrac{15}{60}\) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y \(\times\) ( \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\)) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y = \(\dfrac{17}{15}\) + \(\dfrac{13}{15}\)
y = \(\dfrac{30}{15}\)
y = 2
15 tháng 4 2023
Cái này bằng rủ em chơi oẳn tù tì ,em ra lá còn anh ra hôn má em
HS
1
LN
27 tháng 4 2017
\(\frac{2}{3}x\frac{4}{y}=\frac{4}{45}:\frac{1}{5}\)\(=\frac{4}{15}\)
\(\frac{4}{y}=\frac{4}{15}:\frac{2}{3}\)\(=\frac{2}{5}\)
y=4:\(\frac{2}{5}\) y=10
\(\frac{3}{4}x\frac{y}{5}=\frac{15}{4}\)
\(\frac{y}{5}=\frac{15}{4}:\frac{3}{4}=5\)
y=5x5=25
DC
5
NT
4
H
22 tháng 5 2023
\(y\times\dfrac{13}{2}+4=\dfrac{11}{2}\\ \Rightarrow y\times\dfrac{13}{2}=\dfrac{11}{2}-4\\ \Rightarrow y\times\dfrac{13}{2}=\dfrac{11-4\times2}{2}\\ \Rightarrow y\times\dfrac{13}{2}=\dfrac{3}{2}\\ \Rightarrow y=\dfrac{3}{2}:\dfrac{13}{2}=\dfrac{3}{2}\times\dfrac{2}{13}=\dfrac{3}{13}\)
NT
3
2 tháng 7 2021
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
\(\frac{4}{15}:y=\left(\frac{4}{5}+\frac{1}{2}\right)\times\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{13}{10}\times\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{2}{5}\)
\(y=\frac{4}{15}:\frac{2}{5}\)
\(y=\frac{2}{3}\)
\(\frac{4}{15}:y=\left(\frac{8}{10}+\frac{5}{10}\right)X\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{13}{10}X\frac{4}{13}\)
\(\frac{4}{15}:y=\frac{2}{5}\)
\(y=\frac{4}{15}:\frac{2}{5}\)
\(y=\frac{4}{15}X\frac{5}{2}\)
\(y=\frac{2}{3}\)
HOK TỐT