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a,(x-7)x+1-(x-7)x+11=0
=>(x-7)x+1.[1-(x-7)10]=0
=>(x-7)x+1=0
=>x-7=0
=>x=7
hoặc 1-(x-7)10=1
=>(x-7)10=1
=>x-7=-1;1
=>x=8;6
vậy x=6;7;8
b,(x-1)2=36/49
=>x-1=6/7;-6/7
=>x=13/7;1/7
vậy x=1/7;13/7
a,(x-7)x+1-(x-7)x+11=0
=>(x-7)x+1.[1-(x-7)10]=0
=>(x-7)x+1=0
=>x-7=0
=>x=7
hoặc 1-(x-7)10=1
=>(x-7)10=1
=>x-7=-1;1
=>x=8;6
vậy x=6;7;8
b,(x-1)2=36/49
=>x-1=6/7;-6/7
=>x=13/7;1/7
vậy x=1/7;13/7
\(\left(x-7\right)^{x+1}=\left(x-7\right)^{x+11}=0\)
\(\left(x-7\right)^{x+1}\left[1-\left(x-7\right)^{10}\right]=0\)
\(\Leftrightarrow\left(x-7\right)^{x+1}=0hay1-\left(x-7\right)^{10}=0\)
\(\Leftrightarrow\hept{\begin{cases}x-7=0\\\left(x-7\right)^{10}=1\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=7\\x-7=1\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=7\\x=\left\{6;8\right\}\end{cases}}\)
Vậy \(x\in\left\{6;8\right\}\)
\(.\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
Vậy : x=7
=> (x-7)^x+1 + 1.[1-(x-7)^10] = 0
=> x-7 = 0 hoặc 1-(x-7)^10 = 0
=> x=7 hoặc x = 8 hoặc x = 6
k mk nha
=> (x-7)x+1(1 - (x-7)10) = 0
=> (x-7)x+1 = 0
=> x-7 = 0 => x = 7
hoặc 1 - (x-7)10 = 0
=> (x-7)10 = 1
=> x-7 = 1
=> x = 8
\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\Leftrightarrow\left(x-7\right)^{x+1}.\left[1-\left(x-7\right)^{10}\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x-7\right)^{x+1}=0\\1-\left(x-7\right)^{10}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-7=0\\\left(x-7\right)^{10}=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=8\end{cases}}\)
Tìm x biết:
\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)
(x-7)x+1-(x-7)x+11=0
=>x-7=0
=>x=7
(8x-1)2n+1=52n+1
=>8x-1=5
=>8x=6
=>x=3/4
Tick Đúng Nha
\(\Leftrightarrow\left(x-7\right)^{x+1}\left[1-\left(x-7\right)^{10}\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^{x+1}=0\\\left(x-7\right)^{10}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\end{matrix}\right.\)