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Tìm X
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\)
\(=\frac{1}{5}\)
\(\Rightarrow x-100=\frac{1}{5}\)
\(x=\frac{1}{5}+100\)
\(x=\frac{1}{5}+\frac{500}{5}\)
\(x=\frac{501}{5}\)
a: =>1/3*4+1/4*5+...+1/x(x+1)=10/39
=>1/3-1/4+...+1/x-1/x+1=10/39
=>1/3-1/(x+1)=10/39
=>1/(x+1)=13/39-10/39=3/39=1/13
=>x+1=13
=>x=12
b: =>15x=150
=>x=10
c: =>120-5x=45
=>5x=75
=>x=15
`Answer:`
\(\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+...+\left(x+\frac{1}{729}\right)=\frac{4209}{729}\)
\(\Leftrightarrow\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{3^2}\right)+\left(x+\frac{1}{3^3}\right)+...+\left(x+\frac{1}{3^6}\right)=\frac{4209}{729}\)
\(\Leftrightarrow6x+\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)=\frac{4209}{729}\text{(*)}\)
Đặt \(N=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\)
\(\Leftrightarrow3N=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^5}\)
\(\Leftrightarrow3N-N=\left(1+\frac{1}{3}+\frac{1}{3^2}+..+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)\)
\(\Leftrightarrow2N=1-\frac{1}{3^6}\)
\(\Leftrightarrow2N=\frac{728}{729}\)
\(\Leftrightarrow N=\frac{364}{729}\)
\(\text{(*)}\Leftrightarrow6x+\frac{364}{729}=\frac{4209}{729}\)
\(\Leftrightarrow6x=\frac{3845}{729}\)
\(\Leftrightarrow x=\frac{3845}{4374}\)
x : 2 + x + x : 3 + x : 4 = 26
x : ( 2 + 1 + 3 + 4 ) = 26
x : 10 = 26
x = 26 x 10
x = 260
X : 2 + X + X : 3 + X : 4 = 26
X : (2 + 3 + 4 + 1) =26
X :10 =26
X =26 x 10
X =260
Vậy X = 260
Chúc bạn học tốt
(x + 1 ) + ( x + 2 ) + ( x + 3 ) + ........+ (x + 100) = 5550
x = 100 + ( 1 + 2 + 3 + .........+100)=5550
x = (5550 - 5050 ) : 100
x = 500 : 100
x = 5
2,1 x 100 =210
25,08 x 100=2508
4,061 x 100=406,1
7,2 x 1000=7200
5,32 x 100=532
0,894x1000=894
9,63 x 10=96,3
5,328x10=53,28
2,1 x 100 = 210
25,08 x 100 = 2508
4,061 x 100 = 406100
7,2 x 1000 = 7200
5,32 x 100 = 532
0,894 x 1000 = 894
9,63 x 10 = 96,3
5,328 x 10 = 53.28
Đề bài thiếu dấu cộng ở giữa ( x + 2 ) và ( x + 3 ) nha bạn.
(x+1)+(x+2)+(x+3)+......+(x+100)=5700
=> x + 1 + x + 2 + ... + x + 100 = 5700
=> (x + x + x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5700
100 số hạng
=> x.100 + 5050 = 5700
=> x.100 = 5700 - 5050
=> x.100 = 650
=> x = 650 : 100
=> x = 6,5
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5700
x + 1 + x + 2 + x + 3 + ... + x + 100 = 5700
100x + 1 + 2 + 3 + ... + 100 = 5700
100x + 5050 = 5700
100x = 5700 - 5050
100x = 650
x = 650 : 100
x = 6,5