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c] 7 * x + 8 * x + 9 * x + .... + 100 * x = 1025
(7+8+9+...+100)*x=1025
Coi A= 7+8+...+100
Số các số hạng của A là:
(100-7):1+1=94 (số)
=>A=(100+7)*94:2=5029
Ta lại có:
5029*x=1025
=>x=1025:5019=1025/5019
a, \(x.\left(\frac{3}{2}+\frac{1}{4}-\frac{1}{2}\right)=x.\left(\frac{6}{4}+\frac{1}{4}-\frac{2}{4}\right)=\frac{10}{9}\)
\(x.\frac{5}{4}=\frac{10}{9}\)
\(x=\frac{10}{9}:\frac{5}{4}=\frac{10}{9}.\frac{4}{5}=\frac{8}{9}\)
c] 7 * x + 8 * x + 9 * x + .....+ 100 * x = 1025
=> x (7 + 8 + 9 +...+ 100) = 1025
=> x * 5029 = 1025
=> x = 1025/5029
y+y x 1/3 : 2/9 + y :2/7 = 252
y x 1 + y x (1/3 x 9/2 ) + y x 7/2 = 252
y x 1/1 + y x 3/2 + y x 7/2 = 252
y x (1/1 + 3/2 + 7/2 ) = 252
y x 6 = 252
y = 252 : 6
y = 42
a.
150 + x : 3 = 620 : 4
150 + x : 3 = 155
x : 3 = 155 - 150
x : 3 = 5
x = 5 x 3
x = 15
b.
x * 0,1 = 1/2 -2/5
x * 1/10 = 5/10 - 4/10
x * 1/10 = 1/10
x = 1/10 : 1/10
x = 1
c.
4/9 + 5/9 : x = 1
5/9 : x = 1 - 4/9
5/9 :x = 5/9
x = 5/9 : 5/9
x = 1
1) \(150+x.\frac{1}{3}=155\)
\(\frac{1}{3}x=5\)
\(x=15\)
2) \(x.\frac{1}{10}=\frac{1}{2}-\frac{2}{5}\)
\(\frac{1}{10}x=\frac{5}{10}-\frac{4}{10}\)
\(\frac{1}{10}x=\frac{1}{10}\)
\(x=1\)
3) \(\frac{4}{9}+\frac{9}{5}x=1\)
\(\frac{9}{5}x=\frac{9}{9}-\frac{4}{9}\)
\(\frac{9}{5}x=\frac{5}{9}\)
\(x=1\)
11 x 10 - 10 x 9 + 9 x 8 - 8 x 7 + 7 x 6 - 6 x 5 + 5 x 4 - 4 x 3 + 3 x 2 - 2 x 1 = 60
bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\)
\(x\times\dfrac{11}{16}=2\)
\(x=2:\dfrac{11}{16}\)
\(x=\dfrac{32}{11}\)
Bài 1 :
\(\dfrac{x}{16}\times\left(2017-1\right)=2\)
\(\dfrac{x}{16}\times2016=2\)
\(\dfrac{x}{16}=\dfrac{2}{2016}\)
\(x=\dfrac{2}{2016}\times16\)
\(x=\dfrac{1}{63}\)
\(x-\dfrac{2}{3}.\left(x+9\right)=1\)
\(\Rightarrow x-\dfrac{2}{3}x-6=1\)
\(\Rightarrow\dfrac{1}{3}x=7\)
\(\Rightarrow x=21\)
\(x-\dfrac{2}{3}\times\left(x+9\right)=1\)
\(x-\dfrac{2}{3}x-6=1\)
\(\dfrac{1}{3}x-6=1\)
\(\dfrac{1}{3}x=1+6\)
\(\dfrac{1}{3}x=7\)
\(x=7:\dfrac{1}{3}\)
\(x=21\)