Question

[Đoàn Nguyễn Bảo Long]

Tìm x:

a, 4.( x + 41 ) = 400

b, 4. ( x-3 ) = 7 mũ 2 - 1 mũ 10

Answer 1

[Nguyễn Ngọc Khánh Huyền]

a) \(4\left(x+41\right)=400\)
\(\Rightarrow x+41=400:4\)
\(\Rightarrow x+41=100\)
\(\Rightarrow x=100-41\)
\(\Rightarrow x=59\)

Answer 2

[Tô Mì]

a/ \(4.\left(x+41\right)=400\)

\(x+41=\dfrac{400}{4}=100\)

\(\Rightarrow x=59\)

b/ \(4.\left(x-3\right)=7^2-1^{10}\)

\(4.\left(x-3\right)=49-1\)

\(4.\left(x-3\right)=48\)

\(x-3=\dfrac{48}{3}=16\)

\(\Rightarrow x=19\)

#AEZn8