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Lời giải:
a.
$12x+19x-123=280$
$31x=280+123$
$31x=403$
$x=403:31=13$
b.
$5-(17-3)=x-(2-5)$
$-9=x-(-3)$
$x=(-9)+(-3)=-12$
a.x+8=âm 17
x = - 17 - 8
x = -25
b. ( x - 7 ) + 13 = 25
( x - 7 ) = 25 - 13
( x - 7 ) = 12
x = 12 + 7
x = 19
B1
a.35*18-5*7*28
=35*18-35*28
=35*(-10)
=-350
b.24*(16-5)-16*(24-5)
=(24*16)-24*5-(16*24)-16*5
=384-24*5-384-16*5
=(384-384)-24*5-16*5
=0-24*5-16*5
=5*(-24-16)
=5*(-8)
=-40
c.29*(19-23)-19*(29-13)
=(29*19)-(19*29)*23-13
=(551-551)*23-13
=0*10
=0
d.34+35+36+37-14-15-16-17
=(34-14)+(35-15)+(36-16)+(37-17)
=20+20+20+20
=80
1)
a) \(\left(-175\right)-123+3+175+\left(-3\right)\)
\(=\left[\left(-175\right)+175\right]+\left[3+\left(-3\right)\right]-123\)
\(=0+0-123\)
\(=-123\)
b) \(17.85+15.17-150\)
\(=17.\left(85+15\right)-150\)
\(=17.100-150\)
\(=1700-150\)
\(=1550\)
c) \(176:\left(4.5^2-3.2^2\right)\)
\(=176:\left(4.25-3.4\right)\)
\(=176:\left(100-12\right)\)
\(=176:88\)
\(=2\)
2)
a) \(8-x=-12\)
\(\Rightarrow x=8-\left(-12\right)\)
\(\Rightarrow x=8+12\)
\(\Rightarrow x=20\)
Vậy \(x=20\)
b) \(20+2^3.x=5^2.4\)
\(\Rightarrow20+8.x=25.4\)
\(\Rightarrow20+8.x=100\)
\(\Rightarrow8.x=100-20\)
\(\Rightarrow8.x=80\)
\(\Rightarrow x=80:8\)
\(\Rightarrow x=10\)
Vậy \(x=10\)
c) \(2\left|x-1\right|+5=15\)
\(\Rightarrow2\left|x-1\right|=15-5\)
\(\Rightarrow2\left|x-1\right|=10\)
\(\Rightarrow\left|x-1\right|=10:2\)
\(\Rightarrow\left|x-1\right|=5\)
Xét trường hợp 1: \(x-1=5\)
\(\Rightarrow x=5+1\)
\(\Rightarrow x=6\)
Xét trường hợp 2: \(x-1=-5\)
\(\Rightarrow x=\left(-5\right)+1\)
\(\Rightarrow x=-5+1\)
\(\Rightarrow x=-\left(5-1\right)\)
\(\Rightarrow x=-4\)
Vậy \(x=6\) hoặc \(x=-4\)
Bài 1:
\(a)\left(-175\right)-123+3+175+\left(-3\right)\)
\(=\left[\left(-175\right)+175\right]+\left[\left(-3+3\right)\right]-123\)
\(=0+0-123\)
\(=-123\)
\(b)17.85+15.17-150\)
\(=17.\left(85+15\right)-150\)
\(=17.100-150=1700-150=1550\)
\(c)176:\left(4.5^2-3.2^2\right)\)
\(=176:\left(4.25-3.4\right)\)
\(=176:\left(100-12\right)=176:88=2\)
Bài 2:
\(a)8-x=-12\)
\(\Rightarrow x=8-\left(-12\right)\)
\(\Rightarrow x=20\)
\(b)20+2^3.x=5^2.4\)
\(\Rightarrow20+8.x=25.4\)
\(\Rightarrow20+8.x=100\)
\(\Rightarrow8.x=100-20\)
\(\Rightarrow8.x=80\)
\(\Rightarrow x=80:8=10\)
\(c)2\left|x-1\right|+5=15\)
\(\Rightarrow2\left|x-1\right|=15-5\)
\(\Rightarrow2\left|x-1\right|=10\)
\(\Rightarrow\left|x-1\right|=10:2\)
\(\Rightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
a) x - (11 - x) = -48 + (-12 + x)
x - 11 + x = -48 + (-12) + x
x + x - x = -48 + (-12) + 11
x + 0 = (-60) + 11
x = -49
b) (15 - x) + (x - 12) = 7 - (-8 + x)
15 - x + x - 12 = 7 + 8 + x
15 - x + x - 12 = 15 + x
x + x - x = 15 - 15 + 12
x + 0 = 0 + 12
x = 12
c) (x - 12) - (2x + 31) = -6 - 5
x - 12 - 2x - 31 = -1
x - 12 - 2x = -1 + 31
x - 12 - 2x = 30
x - 2x = 30 + 12
-1x = 42
=> x = -42
d) |x + 5| - (-17) = 20
=> |x + 5| + 17 = 20
=> |x + 5| = 20 - 17
=> |x + 5| = 3
=> \(\orbr{\begin{cases}x+5=3\\x+5=-3\end{cases}}\)
=> \(\orbr{\begin{cases}x=3-5\\x=-3-5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=-8\end{cases}}\)
12x2 - 3x = 0
=> 12x2 - 3x = (22 . 3x2) - 3x = 0
=> 3x . (4x - 1) = 0
=> 3x . 4x - 3x . 1 = 0
=> 3x . 4x - 3x = 0
=> 12x - 3x = 0
=> 4x =0
=> x = 0
a.12x+19x-123=280
12x+19x =280+123
12x+19x =403
31x =403
x=403:31
x=13
b. 5-(17-3)=x-(2-15)
5-14 =x-(-13)
-9 =x+13
=> x=(-9)-13=-22
Tìm x:
a. 12x + 19x - 123 = 280
(12 + 19).x - 123 = 280
31.x - 123 = 280
31.x = 280 + 123
31.x = 403
x = 403 : 31
x = 13