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\(x\cdot\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(x\cdot\frac{3\cdot\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5\cdot\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(x\cdot\frac{3}{5}=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{3}{5}\)
\(x=\frac{25}{9}\)
\(x.\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(x.\frac{3.\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5.\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(x.\frac{3}{5}=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{3}{5}\)
\(x=\frac{25}{9}\)
\(x.\frac{\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3\left(\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5\left(\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3}{5}=\frac{5}{3}\)
\(\Rightarrow x=\frac{5}{3}:\frac{3}{5}=\frac{25}{9}\)
vậy \(x=\frac{25}{9}\)
\(\Rightarrow x.\frac{3\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}{5\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3}{5}=\frac{5}{3}\)
\(\Rightarrow x=\frac{25}{9}\)
\(\left(-1\frac{1}{6}\right)\left(\frac{1-\frac{3}{5}+\frac{3}{11}-\frac{3}{13}}{\frac{1}{3}-\frac{1}{5}+\frac{1}{11}-\frac{1}{13}}\right)\left(\frac{4-\frac{4}{17}+\frac{4}{19}-\frac{4}{2013}}{5-\frac{5}{7}+\frac{5}{19}-\frac{5}{2013}}\right)\)
\(=-\frac{7}{6}.\left(\frac{3\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{11}-\frac{1}{13}\right)}{\frac{1}{3}-\frac{1}{5}+\frac{1}{11}-\frac{1}{13}}\right):\left(\frac{4.\left(1-\frac{1}{7}+\frac{1}{19}-\frac{1}{2013}\right)}{5.\left(1-\frac{1}{7}+\frac{1}{19}-\frac{1}{2013}\right)}\right)\)
\(=-\frac{7}{6}.3:\frac{4}{5}=-\frac{7}{2}.\frac{5}{4}=-\frac{35}{8}\)
tong bang bao nhiu vay
ko có kết quả thì làm sao mà tính được