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a/2x+2-2x=96
2x(22-1)=96
2x3=96
2x=96:3
2x=32
2x=25
x=5
b/(x-1)3=125
(x-1)3=53
x-1=5
x=6
c/(2x+1)3=343
(2x+1)3=73
2x+1=7
2x=6
x=3
(2x+1)3=125
(2x+1 ) 3 = 53
2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
a)15.102 : (2x - 6) = 30
15 . 100 : (2x - 6) = 30
100 : (2x - 6) = 30 : 15
100 : (2x - 6) = 2
2x - 6 = 100 : 2
2x - 6 = 50
2x = 50 + 6
2x = 56
x = 56 : 2
x =28
b) (2x + 1 )3 =125
(2x + 1 )3 = 53
Suy ra 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4:2
x = 2
a )15.102:(2x-6)=30
15.100:(2x-6)=30
100:(2x-6)=30:15
100:(2x-6)=2
2x-6 = 100:2
2x-6 = 50
2x = 50+6
2x = 56
x = 56:2
x = 28
ý b) m chịu
( 2x + 1 )3 = 125
( 2x + 1 )3 = 53
=> 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
Vậy x = 2
\(\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(2x+1=5\)
\(2x=5-1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
Ta có: \(^{\left(2x+1\right)^3=125}\)
=> \(\left(2x+1\right)^3=5^3\)(vì \(5^3\)= 125)
=> 2x+1 = 5
=> 2x = 5-1 = 4
=> x = 4:2
=>x = 2
Vậy x = 2
\(\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow2\)
a) 5x = 125
\(\Rightarrow\)5x = 53
\(\Rightarrow\)x = 3
b, 32x = 81
\(\Rightarrow\)32x = 34
\(\Rightarrow\)2x = 4
\(\Rightarrow\) x = 4 : 2
\(\Rightarrow\) x = 2
c, 52x-3 - 2 . 52 = 52 . 3
52x-3 - 2 . 25 = 25 . 3
52x-3 - 50 = 75
52x-3 = 75 + 50
52x-3 = 125
52x-3 = 53
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3
a, 5x = 125 suy ra 5x = 53 suy ra x = 3
b, 32x = 81 suy ra 32x = 34 suy ra x = 2
c, 52x - 3 - 2.52 = 52 . 3
suy ra 52x : 53 = 52 .3 + 2. 52
suy ra 52x : 53 = 52 . 5
suy ra 52x = 53 . 52 . 53
52x = 56 suy ra 2x = 6 suy ra x = 3
a) 19992x - 6 = 1
19992x - 6 = 19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b) 2x x 4 = 128
2x=128:4
2x=32
2x=25
=>x=5
c) ( 2x + 1 ) 3 = 125
( 2x + 1 ) 3 = 53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2
a)19992x-6=1
19992x-6=19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b)2x.4=128
2x=128:4
2x=32
x=32:2
x=5
c)(2x+1)3=125
(2x+1)3=53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2
( 2x + 1 ) 3 = 125
( 2x + 1 ) 3 = 53
2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
(2x+1)3=125
2x+1=5
2x=5-1
2x=4
x=4:2
x=2