Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) - 0,52 : x = - 9,36 : 16,38
- 0,52 : x = \(-\frac{4}{7}\)
\(x=\left(-0,52\right):\left(-\frac{4}{7}\right)=\frac{91}{100}=0,91\)
b) \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)
\(\frac{x}{1,61}=\frac{34}{23}\)
\(x=\frac{34}{23}.1,61=2,38\)
Tìm x
X/27 = -2/3.6 ; -0,52: x = -9,36 :16,38 ; \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
a, ta có:27:3,6=7,5
=>-2x7,5=15
vậy x cần tìm là 15
b, -0,52:x=\(-\frac{4}{7}\)
\(\frac{-13}{25}\): x=\(\frac{-4}{7}\)
x=\(\frac{-13}{25}:\frac{-4}{7}\)
x=0,91
a)\(\frac{x}{27}=\frac{-2}{3,6}\)
=>x.3,6=27.(-2)
=>x.3,6=-54
=>x=-15
b)-0,52:x=-9,36:16,38
=>-0,52:x=-4/7
=>x=0,91
c)\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
=>\(2\frac{7}{8}.x=4\frac{1}{4}.1,61\)
=>\(2\frac{7}{8}.x=\frac{2737}{400}\)
=>x=\(\frac{119}{50}\)
a,\(\frac{x}{27}=-\frac{2}{3,6}\)
\(\Leftrightarrow x.3,6=27.-2\)
\(\Leftrightarrow x.3,6=-54\)
\(\Leftrightarrow x=-15\)
b,\(-0,52\div x=-9,36\div16,38\)
\(\Leftrightarrow-0,52\div x=-\frac{4}{7}\)
\(\Leftrightarrow x=\frac{91}{100}\)
c,\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\Leftrightarrow\frac{4,25}{2,875}=\frac{x}{1,61}\)
\(\Leftrightarrow x.2,875=4,25.1,61\)
\(\Leftrightarrow x.2,875=6,8425\)
\(\Leftrightarrow x=2,38\)
\(\frac{x}{27}=-\frac{2}{3,6}\)
\(x=\frac{-2\times27}{3,6}\)
\(x=-15\)
***
\(\frac{-0,52}{x}=\frac{-9,36}{16,38}\)
\(x=\frac{-0,52\times16,38}{-9,36}\)
\(x=0,91\)
***
\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\frac{4,25}{2,875}=\frac{x}{1,61}\)
\(x=\frac{4,25\times1,61}{2,875}\)
\(x=2,38\)
\(a.\)
\(\frac{x}{27}=\frac{-2}{3,6}\)
\(\Rightarrow x=\frac{\left(-2\right).27}{3,6}\)
\(\Rightarrow x=\frac{-54}{3,6}\)
\(\Rightarrow x=-15\)
Vậy : \(x=-15\)
\(b.\)
\(-0,52:x=-9,36:16,38\)
\(\Rightarrow\frac{-0,52}{x}=-\frac{4}{7}\)
\(\Rightarrow x=\frac{-0,52.7}{-4}\)
\(\Rightarrow x=0,91\)
Vậy : \(x=0,91\)
\(c.\)
\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\Rightarrow\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)
\(\Rightarrow\frac{17}{4}.\frac{8}{23}=\frac{x}{1,61}\)
\(\Rightarrow\frac{34}{23}=\frac{x}{1,61}\)
\(\Rightarrow x=\frac{1,61.34}{23}\)
\(\Rightarrow x=\frac{119}{50}\)
Vậy : \(x=\frac{119}{50}\)
a) \(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
=> x. 3,6 = 27. (-2)
=> x.3,6 = -54
x = (-54) : 3,6
x = -15
b) -0,52 : x = -9,36 : 16,38
- 0,52 : x = \(\dfrac{-4}{7}\)
x = \(\dfrac{-4}{7}\) . ( -0,52)
x = \(\dfrac{52}{175}\)
\(a,-0,52:x=-9,36:16,38\)
\(\Leftrightarrow\frac{-13}{25}:x=\frac{-4}{7}\)
\(\Leftrightarrow x=\frac{-13}{25}:\frac{-4}{7}\)
\(\Leftrightarrow x=\frac{91}{100}\)
\(b,\frac{x}{-15}=\frac{-60}{x}\)
\(\Leftrightarrow x^2=900\)
\(\Leftrightarrow x^2=\left(30,-30\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x=30\\x=-30\end{cases}}\)
\(c,\frac{-2}{x}=\frac{-x}{8}\)
\(\Leftrightarrow-\left(x^2\right)=-16\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x^2=\left(4,-4\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=4\end{cases}}\)
\(d.3,8\div2x=\frac{1}{4}:2\frac{2}{3}\)
\(\Leftrightarrow3,8\div2x=\frac{3}{32}\)
\(\Leftrightarrow2x=3,8\div\frac{3}{32}\)
\(\Leftrightarrow2x=\frac{608}{15}\)
\(\Leftrightarrow x=\frac{608}{15}\div2\)
\(\Leftrightarrow x=\frac{304}{15}\)
\(e.0,25x\div3=\frac{5}{6}:0,125\)
\(\Leftrightarrow0,25x\div3=\frac{20}{3}\)
\(\Leftrightarrow0,25x=\frac{20}{3}.3\)
\(\Leftrightarrow\frac{1}{4}x=20\)
\(\Leftrightarrow x=20:\frac{1}{4}\)
\(\Leftrightarrow x=80\)
-0,52 : x = -9,36 : 16,38
-0,52 : x = \(-\frac{4}{7}\)
\(-\frac{13}{25}:x=-\frac{4}{7}\)
\(x=-\frac{13}{25}:\left(-\frac{4}{7}\right)\)
\(x=\frac{91}{100}\)
b, \(\frac{17}{\frac{4}{\frac{23}{8}}}=\frac{x}{1,61}\)
=> \(\frac{17}{4}:\frac{23}{8}=\frac{x}{1,61}\)
\(\frac{34}{23}=\frac{x}{1,61}\)
23x = 34 . 1,61 = 54,74
=> x = 54,74 : 23
=> x = 2,38