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\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)
a, BCNN(210;280) = 840 => BC(210;280) = 840k (k ∈ N)
b, BCNN(105;135) = 945 => BC(105;135) = 945k (k ∈ N)
c, BCNN(24;36) = 72 => BC(24;36) = 72k (k ∈ N)
d, BCNN(48;80;72) = 720 => BC(48;80;72) = 720k (k ∈ N)
e, BCNN(42;55;91) = 30030 => BC(42;55;91) = 30030k (k ∈ N)
f, BCNN(12;36;102) = 612 => BC(12;36;102) = 612k (k ∈ N)
đơn giản!!!
a) 18, 42
18 = 2 . 3\(^2\)
42 = 2 . 3 . 7
ƯCLN(18, 42) = 2 . 3\(^2\)= 18
b) 28, 48
28 = 2\(^2\). 7
48 = 2\(^4\). 3
ƯCLN(28, 48) = 2\(^4\)= 16
chúc may mắn!