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a)
<=> 219 - 7x - 7 = 100
<=> -7x = 100 - 219 + 7
<=> -7x = -112
<=> x = -112 : (-7)
<=> x = 16
b)
<=> 9x - 18 = 34
<=> 9x = 34 + 18
<=> 9x = 52
<=> x = 52 : 9
<=> x = 52/9
a)219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1 =119:7
x+1 =17
x =17-1
x =16
b) (3x-6).3=34
3x-6 =34:3
3x-6 =\(\frac{34}{3}\)
3x =\(\frac{34}{3}\)- 6
3x =\(\frac{16}{3}\)
x =\(\frac{16}{3}\): 3
x =\(\frac{16}{9}\)
a)219-7(x+1)=100
7(x+1)=219-100
x+1=119/7
x+1=17
x=17-1
x=16
b)(3x-6)*3=64
3x-6=64/3
3x=64/3+6
3x=82/3
x=82/3:3
x=82/9
a) 219-7(x+1)=100
219-7x-7=100
-7x=100-219+7
-7x=-112
x=16
b) (3x-6).3=64
3x-6=64/3
3x=82/3
x=82/9
a)219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
x=17-1
x=16
b)(3x-6).3=34
(3x-6).3=81
3x-6=81:3
3x-6=17
3x=27+6
3x=33
x=33:3
x=11
li-ke cho mình nha Duong Thi Hoai My
a)
\(219-7\left(x+1\right)=100\)
\(\Rightarrow7\left(x+1\right)=119\)
\(\Rightarrow x+1=17\)
=> x = 16
Vậy x = 16
b)
\(\left(3x-6\right)3=3^4\)
\(\Rightarrow\left(x-2\right)3^2=3^4\)
=> x - 2 = 9
=> x = 7
Vậy x = 7
a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
219 - 7(x+1)=100 (3x-6).3=34
=> 7(x+1)=219-100 => 3x-6=34:3
=> 7(x+1)=119 => 3x-6=32=9
=> x+1=119:7 => 3x=9+6
=> x+1=17 => 3x=15
=> x=17-1 => x=15:3
=> x=16 => x=5
Vậy x=16 Vậy x=5
a) 219 - 7 (x + 1) = 100
7 ( x + 1)= 219 -100
7 ( x+ 1) =119
x+1=119 : 7
x+1=17
x=17-1
x= 16
a) 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119:7
x+1=17
=> x = 16
b)(3x-6).3 = 3^4
(3x-6).3 = 81
3x-6= 81:3
3x-6= 27
3x = 27-6
3x=21
=> x= 7.
kik nha
Bài 10:
a: 2x-3 là bội của x+1
=>\(2x-3⋮x+1\)
=>\(2x+2-5⋮x+1\)
=>\(-5⋮x+1\)
=>\(x+1\in\left\{1;-1;5;-5\right\}\)
=>\(x\in\left\{0;-2;4;-6\right\}\)
b: x-2 là ước của 3x-2
=>\(3x-2⋮x-2\)
=>\(3x-6+4⋮x-2\)
=>\(4⋮x-2\)
=>\(x-2\inƯ\left(4\right)\)
=>\(x-2\in\left\{1;-1;2;-2;4;-4\right\}\)
=>\(x\in\left\{3;1;4;0;6;-2\right\}\)
Bài 14:
a: \(4n-5⋮2n-1\)
=>\(4n-2-3⋮2n-1\)
=>\(-3⋮2n-1\)
=>\(2n-1\inƯ\left(-3\right)\)
=>\(2n-1\in\left\{1;-1;3;-3\right\}\)
=>\(2n\in\left\{2;0;4;-2\right\}\)
=>\(n\in\left\{1;0;2;-1\right\}\)
mà n>=0
nên \(n\in\left\{1;0;2\right\}\)
b: \(n^2+3n+1⋮n+1\)
=>\(n^2+n+2n+2-1⋮n+1\)
=>\(n\left(n+1\right)+2\left(n+1\right)-1⋮n+1\)
=>\(-1⋮n+1\)
=>\(n+1\in\left\{1;-1\right\}\)
=>\(n\in\left\{0;-2\right\}\)
mà n là số tự nhiên
nên n=0
a. 219 - 7(x+1) = 100
7(x+1)=119
x+1=119:7
x+1=17
x=16
Vậy x=16
b. (3x - 6) . 3 = 34
3x-6=34:3
3x-6=33
3x=33
x=11
Vậy x=11
a) \(219-7\left(x+1\right)=100\)
\(\Leftrightarrow219-7x-7=100\)
\(\Leftrightarrow-7x=100-219+7=-112\)
\(\Leftrightarrow x=16\)
b) \(\left(3x-6\right)\cdot3=3^4\)
\(\Leftrightarrow\left(x-2\right)\cdot3^2=3^4\)
\(\Leftrightarrow x-2=3^2\)
\(\Leftrightarrow x=9+2=11\)