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a) x3 - 23 = 25 - ( 316 : 314 + 28 : 2 6 )
x3 - 23 = 25 -( 32 + 22 )
x3 - 23 = 25- ( 9 + 4 )
x3 - 23= 25 - 13
x3 - 8 = 32 - 13
x3 - 8 = 19
x3 = 19 + 8
x3 = 27
x3 = 33
=> x = 3
Vậy x =3
b) ( x2 - 1)4 = 81
( x2 - 1 )4 = 34
=> x2 - 1 = 3
x2 = 3 + 1
x2 = 4
x2 = 22
=> x = 2
Vậy x= 2
c) 5x-2 - 32 = 24 - (68 : 66 - 62 )
5x-2 - 32 = 16 - ( 62 - 62)
5x-2 - 9 = 16 - 0
5x-2 - 9= 16
5x - 2 = 16 + 9
5x - 2 = 25
5x - 2 = 52
=> x - 2 = 2
x = 2 + 2
x = 4
Vậy x = 4
d) 3x + 42 = 196 : ( 193 . 192 ) 3.12005
3x + 16 = 196 : 195 . 3 . 1
3x + 16 = 19 . 3
3x + 16 = 57
3x = 57 - 16
3x = 41
Hình như phép này đề bài sai rồi thì phải
a: \(\Leftrightarrow\left[\left(3x+14\right):4-3\right]:2=1\)
=>(3x+14):4-3=2
=>(3x+14):4=5
=>3x+14=20
=>3x=6
hay x=2
b: \(\Leftrightarrow\left[\left(x:4+17\right):10+3\cdot16\right]:10=5\)
\(\Leftrightarrow\left(x:4+17\right):10=50-48=2\)
=>x:4+17=20
=>x:4=3
hay x=12
c: \(\Leftrightarrow2\cdot15^2+\left[2\cdot125-\left(2x+4\right)\cdot5\right]:19=453\)
\(\Leftrightarrow250-\left(2x+4\right)\cdot5=\left(453-450\right)\cdot19=57\)
=>5(2x+4)=197
=>2x+4=197/5
=>2x=177/5
hay x=177/10
d: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)
=>19x+50=126
=>19x=76
hay x=4
e: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}\)
\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)
hay x=14
f: \(\Leftrightarrow3\left(x+2\right):7=30\)
=>3(x+2)=210
=>x+2=70
hay x=68
g: \(2480-1570+200-x+5=1010\)
=>1115-x=1010
hay x=105
\(=10-\left[\left(91-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[43.5+88\right]:28\)
\(=10-\left[215+88\right]:28\)
\(=10-303:28\)
\(=10-10,821\)
\(=0,179\)
Ko chắc
\(a.\left(5+2\right).x=36-1\)
\(7.x=35\)
\(x=5\)
\(b.\left(5+1\right).x=75+3\)
\(6.x=78\)
\(x=13\)
\(c.\left(6+1\right).x=5^2+3\)
\(7.x=25+3\)
\(7.x=28\)
\(x=4\)
\(d.\left(7-1\right).x=5^2+3.4-1\)
\(6.x=25+12-1\)
\(6.x=36\)
\(x=6\)
1) \(2^{x+1}\cdot2^{2014}=2^{2015}\)\(\Leftrightarrow2^{2014x+2014}=2^{2015}\)\(\Leftrightarrow2014x+2014=2015\)\(\Leftrightarrow x=\frac{1}{2014}\)
2) \(7x-2x=\frac{6^{17}}{6^{15}}+\frac{44}{11}\)\(\Leftrightarrow5x=6^2+4=36+4=40\)\(\Leftrightarrow x=\frac{40}{5}=8\)
3) \(3^x=9\)\(\Leftrightarrow3^x=3^2\)\(\Leftrightarrow x=2\)
4) \(7x-x=\frac{5^{21}}{5^{19}}+3\cdot2^2-7^0\)\(\Leftrightarrow6x=5^2+3\cdot4-1=25+12-1=36\)\(\Leftrightarrow x=6\)
5) \(4^x=64\)\(\Leftrightarrow4^x=4^3\)\(\Leftrightarrow x=3\)
6) \(9^{x-1}=9\)\(\Leftrightarrow x-1=1\)\(\Leftrightarrow x=0\)
7) \(\frac{2^x}{2^5}=1\)\(\Leftrightarrow2^{x-5}=2^0\)\(\Leftrightarrow x-5=0\)\(\Leftrightarrow x=5\)
8) \(\left(5x-9\right)^3=216\)\(\Leftrightarrow\left(5x-9\right)^3=6^3\)\(\Leftrightarrow5x-9=6\)\(\Leftrightarrow5x=15\)\(\Leftrightarrow x=3\)
9) \(5\cdot3^{7x-11}=135\)\(\Leftrightarrow5.3^{7x-11}=5.3^3\)\(\Leftrightarrow3^{7x-11}=3^3\)\(\Leftrightarrow7x-11=3\)\(\Leftrightarrow7x=14\Leftrightarrow x=2\)
10) \(2.3^x=19\cdot3^8-81^2\)\(\Leftrightarrow2.3^x=19\cdot3^8-3^8=18.3^8=2.3^{11}\)\(\Leftrightarrow3^x=3^{11}\Leftrightarrow x=11\)
Đây là cách làm của mình. Bạn có thể chỉnh sửa tuỳ ý theo cách làm của bạn nhé ^^
Học tốt ^3^
Bài 1 :
a/ \(a^3.a^9=a^{3+9}=a^{12}\)
b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)
c/ \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)
d/ \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)
e/ \(5^6:5^3+3^3.3^2\)
\(=5^3+3^5=125+243=368\)
i/ \(4.5^2-2.3^2\)
\(=2^2.5^2-2.3^2\)
\(=2^2.25-2^2.14\)
\(=2^2.\left(25-14\right)\)
\(=2^2.11\)
\(=4.11=44\)