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\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(16.4^{x+1}-3.4^{x+1}=13.4^{11}\)
\(\left(16-3\right).4^{x+1}=13.4^{11}\)
\(13.4^{x+1}=13.4^{11}\)
\(\Rightarrow x+1=11\)
\(x=10\)
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
=> \(4^{x+1}.\left(4^2-3\right)=13.4^{11}\)
=> \(4^{x+1}.\left(16-3\right)=13.4^{11}\)
=> \(4^{x+1}.13=13.4^{11}\)
=> \(x+1=11\)
=> \(x=11-1=10\)
(x - 2/3)3 = -1/27
=> (x - 2/3)3 = (-1/3)3
=> x - 2/3 = -1/3
=> x = -1/3 + 2/3
=> x = 1/3
Từ bài ra ta có \(\left(x-\frac{2}{3}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow x-\frac{2}{3}=\frac{-1}{3}\)
\(\Rightarrow x=\frac{-1}{3}+\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{3}\)
Vậy ... nếu đúng thì k nha
\(\Rightarrow\frac{x+1+y+2+z+3}{3+4+5}\)
\(\Rightarrow\frac{24}{12}=2\)
\(\frac{x+1}{3}=2\Rightarrow x=5\)
\(\frac{y+2}{4}=2\Rightarrow y=6\)
\(\frac{z+3}{5}=2\Rightarrow z=7\)
\(\frac{5}{x-2}=\frac{15}{6}\)
\(\Rightarrow15x-30=30\)
\(15x=60\)
\(x=4\)
1;Ta có\(5.3^x=5.3^4\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
2.Ta có \(9.5^x=6.5^6+3.5^6\)
\(\Rightarrow9.5^x=5^6.\left(6+3\right)\)
\(\Rightarrow9.5^x=9.5^6\)
\(\Rightarrow5^x=5^6\)\
\(\Rightarrow x=6\)
3, Ta có \(2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(\Rightarrow3^{x+1}.\left(2.3+4\right)=10.3^6\)
\(\Rightarrow3^{x+1}.10=10.3^6\)
\(\Rightarrow3^{x+1}=3^6\)
\(\Rightarrow x+1=6\)
\(\Rightarrow x=5\)
a) 5.3x = 5.34
=> 3x=34
=> x=4
b) 9.5x=6.56+3.56
=> 9.5x = (6+3)56
=> 9.5x=9.56
=> 5x=56
=> x=6
c) 2.3x+2 + 4.3x+1 = 10.36
=> 2.3x+1.3 + 4.3x+1 = 10.36
=> 6.3x+1+4.3x+1=10.36
=> (6+4).3x+1=10.36
=> 10.3x+1=10.36
=> 3x+1=36
=> x+1=6
=> x=5
\(\frac{2^{12}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}\)
\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(=\frac{2^{12}.\left(3^5-3^4\right)}{2^{12}.\left(3^6+3^5\right)}\)
\(=\frac{3^5-3^4}{3^6+3^5}=\frac{3^4.\left(3-1\right)}{3^5\left(3+1\right)}\)
\(=\frac{3^4.2}{3^5.4}=\frac{3^4.2}{3^4.3.4}=\frac{2}{12}=\frac{1}{6}\)
P/s: Hoq chắc ạ (: Ms lp 6 lm đại
\(\frac{x}{2}=\frac{y}{3}\)
\(\Leftrightarrow\frac{x}{8}=\frac{y}{12}\)(1)
\(\frac{y}{4}=\frac{z}{5}\)
\(\Leftrightarrow\frac{y}{12}=\frac{z}{15}\)(2)
Từ (1) (2)
\(\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{z}{15}=\frac{x+y-z}{8+12-15}=\frac{10}{5}=2\)
\(\Rightarrow\hept{\begin{cases}x=2.8\\y=2.12\\z=2.15\end{cases}\Rightarrow}\hept{\begin{cases}x=16\\y=24\\z=30\end{cases}}\)
2.3x+2+4.3x+1=10.36
2.3.3x+1+4.3x+1=10.36
6.3x+1+4.3x+1=10.36
10.3x+1=10.36
=>3x+1=36
=>x+1=6 =>x=5
Ai thấy đúng cho mình nha!
\(2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(2.3^{x+2}+2^2.3^{x+1}=2.5.3^6\)
\(2.3^{x+1}\left(3+2\right)=2.5.3^6\)
\(2.3^{x+1}.5=2.5.3^6\)
\(\Rightarrow x+1=6\Rightarrow x=5\)