Question

[shadow fight 2]

tim o tu nhien y biet

a, (y-6)^2=(y-6)^3

b, 3+2^Y-1=24-(4^2-(2^2-1))

Answer 1

[Nguyệt]

\(\left(y-6\right)^3-\left(y-6\right)^2=0\)

\(\left(y-6\right)^2.\left[\left(y-6\right)-1\right]=0\)

\(=>\orbr{\begin{cases}y^2-6=0\\y-7=0\end{cases}}\) \(=>\orbr{\begin{cases}y=6\\y=7\end{cases}}\)

Vậy ...

Answer 2

[Nguyệt]

vt lộn đoạn y^2-6=0 thành (y-6)^2 nha

sorry