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Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
Call a is the 3-digit number which divied by 57, the remainder is 27, divided by 217, the remainder is 60.
\(\Rightarrow\)a-27\(⋮\)57
\(\Rightarrow\)a-60\(⋮\)217
Because 684 is a multiple of 57 so:
\(\Rightarrow\)a-27-684\(⋮\)57\(\Rightarrow\)a-771\(⋮\)57
Because 651 is a multiple of 217 so:
\(\Rightarrow\)a-60-651\(⋮\)217\(\Rightarrow\)a-771\(⋮\)217
\(\Rightarrow\)a-771 \(\in\)CM(217;57)
\(\Rightarrow\)a-771\(\in\){0;12369;...}
\(\Rightarrow\)a\(\in\){771;13140;...}
Because a is a 3-digit number so a = 771.
The number is 771.
Số dư luôn bé hơn số chia
=> số dư lớn nhất nếu số chia là 18 là :
18 - 1 = 17
đ/s : ...
Translate: Số dư lớn nhất trong phép chia cho 18.
Answer: 17 (Seventeen)