Question

[oOo Min min oOo]

so sánh \(\sqrt{\sqrt{6+\sqrt{20}}}\) và \(\sqrt{1+\sqrt{6}}\)

Answer 1

[Thuỷ Thủ Sao Kim]

m kmnhbk5htb ,k55555555555555555555555555555555555e,

Answer 2

[Lê Quốc Anh]

\(\sqrt{\sqrt{6+\sqrt{20}}}=\sqrt{\sqrt{6+2\sqrt{5}}}=\sqrt{\sqrt{\left(\sqrt{5}+1\right)^2}}=\sqrt{\sqrt{5}+1}\)

Vì \(\sqrt{\sqrt{5}+1}< \sqrt{\sqrt{6}+1}\Rightarrow\sqrt{\sqrt{6+\sqrt{20}}}< \sqrt{1+\sqrt{6}}\)