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a, Ta có : \(\frac{5+10}{24}=\frac{15}{24}\)
\(\frac{5}{8}=\frac{5.3}{8.3}=\frac{15}{24}\)
\(\Rightarrow\frac{5}{24}< \frac{5+10}{24}=\frac{5}{8}\)
b,Ta có : \(\frac{4}{9}=\frac{4.6}{9.6}=\frac{24}{54}\)
\(\frac{6+9}{6.9}=\frac{15}{54}\)
\(\frac{2}{3}=\frac{2.18}{3.18}=\frac{36}{54}\)
\(\Rightarrow\frac{15}{54}< \frac{24}{54}< \frac{36}{54}\)
\(\Rightarrow\frac{6+9}{6.9}< \frac{4}{9}< \frac{2}{3}\)
a) \(\frac{5+10}{24}=\frac{15}{24}\); \(\frac{5}{8}=\frac{5.3}{8.3}=\frac{15}{24}\)
\(\Rightarrow\frac{5}{24}< \frac{15}{24};\frac{5+10}{24}=\frac{5}{8}\)
b) \(\frac{6+9}{6.9}=\frac{15}{54}\); \(\frac{4}{9}=\frac{24}{54};\frac{2}{3}=\frac{36}{54}\)
\(\Rightarrow\frac{15}{54}< \frac{24}{54}< \frac{36}{54}\)\(\Rightarrow\frac{6+9}{6.9}< \frac{4}{9}< \frac{2}{3}\)
a) ta có \(\frac{5}{24};\frac{15}{24};\frac{5}{8}\)
=>\(\frac{5}{24}< \frac{15}{24}< \frac{20}{24}\)quy đồng lên
b)\(\frac{4}{9};\frac{6+9}{6\cdot9};\frac{2}{3}\)
=>\(\frac{4}{9};\frac{15}{54};\frac{2}{3}\)
=>\(\frac{24}{54};\frac{15}{54};\frac{36}{54}\)
=>\(\frac{15}{54}< \frac{24}{54}< \frac{36}{54}\)
Ta có:\(\frac{4}{9}=\frac{4\cdot6}{9\cdot6}=\frac{24}{54}\) ; \(\frac{6+9}{6\cdot9}=\frac{15}{54}\) ; \(\frac{2}{3}=\frac{2\cdot18}{3\cdot18}=\frac{36}{54}\)
=>\(\frac{15}{54}<\frac{24}{54}<\frac{36}{54}\)
=>\(\frac{6+9}{6\cdot9}<\frac{4}{9}<\frac{2}{3}\)
\(\frac{4}{9}=\frac{4}{9}=\frac{8}{18}\)
\(\frac{6+9}{6.9}=\frac{15}{54}=\frac{5}{18}\)
\(\frac{2}{3}=\frac{12}{18}\)
Vì \(\frac{5}{18}< \frac{8}{18}< \frac{12}{18}\)
Vậy \(\frac{6+9}{6.9}< \frac{4}{9}< \frac{2}{3}\)
Ta có:
1 = \(\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+............+\frac{1}{10}\)(10 phân số \(\frac{1}{10}\))
Mà \(\frac{1}{2}>\frac{1}{10};\frac{2}{3}>\frac{1}{10};............;\frac{9}{10}>10\)
\(\Rightarrow M>1\)
Vậy M > 1
a)5/24<5+10/24=15/24=5/8
=>5/24<10/24<5/8
b)2/3>4/9>6+9/6*9=15/54=5/18
=>2/3>4/9>6+9/6*9
\(a.\frac{5}{24}<\frac{5+10}{24}=\frac{15}{24}=\frac{5}{8}\)
\(b.\frac{2}{3}>\frac{4}{9}>\frac{6+9}{6.9}=\frac{15}{54}=\frac{5}{18}\)