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Bài 1:
a) Ta có: \(13A=\dfrac{13^{16}+13}{13^{16}+1}=1+\dfrac{12}{13^{16}+1}\)
\(13B=\dfrac{13^{17}+13}{13^{17}+1}=1+\dfrac{12}{13^{17}+1}\)
Vì \(\dfrac{12}{13^{16}+1}>\dfrac{12}{13^{17}+1}\Rightarrow1+\dfrac{12}{13^{16}+1}>1+\dfrac{12}{13^{17}+1}\)
\(\Rightarrow13A>13B\)
\(\Rightarrow A>B\)
Vậy A > B
b) Ta có: \(1999C=\dfrac{1999^{2000}+1999}{1999^{2000}+1}=1+\dfrac{1998}{1999^{2000}+1}\)
\(1999D=\dfrac{1999^{1999}+1999}{1999^{1999}+1}=1+\dfrac{1998}{1999^{1999}+1}\)
\(\dfrac{1998}{1999^{2000}+1}< \dfrac{1998}{1999^{1999}+1}\Rightarrow1+\dfrac{1998}{1999^{2000}+1}< 1+\dfrac{1999}{1999^{1999}+1}\)
\(\Rightarrow1999C< 1999D\)
\(\Rightarrow C< D\)
Vậy C < D
Ta có: \(\frac{11}{37}=\frac{11.2}{37.2}=\frac{22}{74}\)
Vì \(74>73\)\(\Rightarrow\frac{1}{74}< \frac{1}{73}\)\(\Rightarrow\frac{22}{74}< \frac{22}{73}\)
hay \(\frac{11}{37}< \frac{22}{73}\)
Bài 52 :
a) 14/21 = 2/3 và 60/72 = 5/6
Vì 2/3 = 4/6 < 5/6 nên 2/3 < 5/6
Bài 53 :
a) Vì 200 < 314 nên 17/200 > 17/314
b) Ta có 11/54 < 11/37 < 22/37 nên 11/54 < 22/37
a)17/200>17/314
b)11/54=22/108<22/37
c)141/893=3/19;159/901=3/17 nên 141/893<159/901
Kết bn với mik nha!
a ) 2 3 < 4 5 b ) 13 − 27 > 39 − 37 ; c ) − 3 7 < − 2 9 d ) − 2 − 7 < − 5 − 17
a ) Ta có
\(\frac{29}{33}>\frac{29}{37}\)( đồng tử khác mẫu )
\(\frac{22}{37}< \frac{29}{37}\)( đồng mẫu khác tử )
=> \(\frac{29}{33}>\frac{29}{37}>\frac{22}{37}\)
b ) \(\frac{163}{257}< \frac{163}{221}\)
\(\frac{162}{257}>\frac{149}{257}\)
\(\Rightarrow\frac{163}{221}>\frac{163}{257}>\frac{149}{257}\)
a) ta có: \(\frac{22}{37}< \frac{29}{37}\)
\(\frac{29}{33}>\frac{29}{37}\)
\(\Rightarrow\frac{22}{37}< \frac{29}{37}< \frac{29}{33}\)
b) ta có: \(\frac{163}{257}>\frac{149}{257}\)
\(\frac{163}{221}>\frac{163}{257}\)
\(\Rightarrow\frac{163}{221}>\frac{163}{257}>\frac{149}{257}\)